Answer:
1. Open the form in the standard form view.
2. Put the cursor in the field to use for sorting.
3. Open the Home tab
4. In the Sort & Filter group, click ascending or descending
Explanation:
Took the test :)
The effectiveness of using thicker bags are:
- It has the lowest environmental impact in terms of any other disposable bag.
- It can be used three to six more times.
- It is environmentally sustainable.
<h3>What is the effect of thicker plastic bags have on the environment?</h3>
The use of plastic bags is known to have some form of detrimental effects on the such as animal choking, pollution, and others.
Conclusively, Note that thicker bags needs a lot of plastic to be able to produce it and it goes to waste even if a person do not use it again.
Learn more about environment from
brainly.com/question/17413226
B. False, it doesnt only have to be applied word by word
Answer:
This article shows how to use regex to remove spaces in between a String.
A string with spaces in between.
String text = "Hello World Java.";
We want to remove the spaces and display it as below:
Hello World Java.
1. Java regex remove spaces
In Java, we can use regex \\s+ to match whitespace characters, and replaceAll("\\s+", " ") to replace them with a single space.
Regex explanation.
`\\s` # Matches whitespace characters.
+ # One or more
StringRemoveSpaces.java
package com.mkyong.regex.string;
public class StringRemoveSpaces {
public static void main(String[] args) {
String text = "Hello World Java.";
String result = text.replaceAll("\\s+", " ");
System.out.println(result);
}
}
Output
Terminal
Hello World Java.
Stack is LIFO data structure (Last In First Out) where the last element entered in stack will be the last one to be out of stack. It has three operations: push() : used to insert an element in stack, pop() : used to delete an element from the stack, top() : used to return the top of the stack i.e. the newest member of the stack. All these operations will take place at the top.
<u>Explanation:</u>
Now, looking at the program, x and y are initialized the values of 2 and 3 respectively. The stack pushes 8 onto the stack making it the first member of the stack. Then the value of x which is 2 is pushed onto the stack. Next, (x+5) = (2+5) = 7 is pushed onto the stack.
Pop() is used to delete hence 7 is popped out from the stack. top() is assigned to y which is 2 in this case and again 2 is popped out from the stack. Now, (x+y) = (2+2) = 4 is pushed onto the stack. And the top() is assigned to x which is 4. 4 is again popped out from the stack. Hence the value of x is 4.
