<span>A. Certificate of License</span>
Answer:
Output: 2004 2008 2058
Explanation:
In the first printf command it will print the address of the variables num, msg1, msg2. And in the second printf command it will print the values of the variables num, msg1, msg2. As the address of the structure is 2004 And the size of the integer is 4 byte so size will increase with 4 bytes and the size of character is 1 byte so it will increase by 1*50= 50 bytes.
Hence, the output is 2004 2008 2058
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