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3 years ago

5x-2y=3 in point-slope form

Mathematics

1 answer:

noname [10]3 years ago

6 0

2y = 5x - 3
y =( 5x-3 )/2

slope = 5
x = 3/5
y = 3/2

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Solve for f <br> 0.3=0.5f-0.7

erastovalidia [21]

Answer:

f=2

Step-by-step explanation:

0.3+0.5f-0.7

Move the varibale (0.5f) to the left-hand side and change it's sign to negative.

-0.5+0.3+-0.7

Move the constant to the right hand side and change it's sign

-0.5f=-0.7-0.3

Calulate the differnce

-0.5f=-1

divide both sides by -0.5

F=2

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Recall from Intermediate Algebra that two non-vertical lines are perpendicular if and only if they have negative reciprocal slop

OLEGan [10]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The line is $y = -4 x$

Step-by-step explanation:

From the question we are told that

The line is $y = \frac{1}{4} x + 8$

The point is P(0,0 )

Generally the equation for a line is $yn = mx + c$

Now comparing this with the given equation we see that

$m =\frac{1}{4} = slope$

$C =8 = intercept$

Generally the slope of the perpendicular to the given line is mathematically evaluated as

$m_1 = - \frac{1}{m}$

=> $m_1 = - \frac{1}{ \frac{1}{4}}$

=> $m_1 = -4$

Generally from the univesal equation of a line and the given point we have that

y = mx + c at p(0,0) and $m_1 = -4$ is

0 = -4 (0 ) + c

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Hence the equation perpendicular to the line given at the point given is

$y = -4 x$

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