Answer:
The right answer is letter C.
Step-by-step explanation:
I hope it's help
have a nice day and night
Answer:
The answer is suppose to be -15.
Step-by-step explanation:
I do not see any statements
I can give you an explanation
Layla forgot to carry the negative
From the equation we see that the center of the circle is at (-2,3) and the radius is 9.
So using the distance formula we can see if the distance from the center to the point (8,4) is 9 units from the center of the circle...
d^2=(8--2)^2+(4-3)^2 and d^2=r^2=81 so
81=10^2+1^2
81=101 which is not true...
So the point (8,4) is √101≈10.05 units away from the center, which is greater than the radius of the circle.
Thus the point lies outside or on the exterior of the circle...
We need to determine the radius and diameter of the circle. If the area of the circle is 10 pi in^2, then, according to the formula for the area of a circle,
A = 10 pi in^2 = pi*r^2. Thus, 10 in^2 = r^2, and r = radius of circle = sqrt(10) in.
Thus, the diam. of the circle is 2sqrt(10) in. This diam. has the same length as does the hypotenuse of one of the triangles making up the square.
Thus, [ 2*sqrt(10) ]^2 = x^2 + x^2, where x represents the length of one side of the square. So, 4(10) in^2 = 2x^2. Then:
40 in^2 = 2x^2, or 20 in^2 = x^2, and so the length x of one side of the square is sqrt(20). The area of the square is the square of this result:
Area of the square = x^2 = [ sqrt(20) ]^2 = 20 in^2 (answer). Compare that to the 10 pi sq in area of the circle (31.42 in^2).
Answer:
both are -10
Step-by-step explanation:
#1
x1 y1 x2 y2
1.5 180 6 135
(Y2-Y1) (135)-(180)= -45 ΔY -45
(X2-X1) (6)-(1.5)= 4.5 ΔX 4.5
slope= -10
B= 195
Y =-10X +195
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#2
x1 y1 x2 y2
1 175 8 105
(Y2-Y1) (105)-(175)= -70 ΔY -70
(X2-X1) (8)-(1)= 7 ΔX 7
slope= -10
B= 185
Y =-10X +185
