The equation you can use to solve the problem is;
50/30 = 300/x
Next Cross Multiply
50x = 9000
x = 9000/50
x = 180
The building's shadow is 180 feet tall
38.50 = 100%
31.57 = ?
Multiply: 31.57 x 100 = 3,157
Divide: 3,157 ÷ 38.50 = 82%
100-82= 18% discount
Answer:
We know that our world is in 3 dimensions i.e. there are three directions and so, three co-ordinates are required.
Now, if we have to find a position of an object lying on a flat surface, this means that there are only two directions and so, two co-ordinates are needed.
So, we can define the domain ( xy-axis ) in such a way that there are two axis - horizontal where right area have positive values & left area has negative values and vertical where upward side have positive values & downward side has negative values.
For e.g. if we want to find the position of a pen on the table. We will make our own xy-axis and see in which quadrant the pen lies.
Let us say that the pen lies at (2,3), this means that the position of pen is in the first quadrant or it is 2 units to the right of y-axis and 3 units up to the x-axis.
This way we can see that two directions are sufficient to find the position of an object placed on a flat surface.
Answer:
Step-by-step explanation:-16x^2 + 24x + 16 = 0.
A. Divide by 8:
-2x^2 + 3x + 2 = 0, A*C = -2*2 = -4 = -1 * 4. Sum = -1 + 4 = 3 = B, -2x^2 + (-x+4x) + 2 = 0,
(-2x^2-x) + (4x+2) = 0,
-x(2x+1) + 2(2x+1) = 0,
(2x+1)(-x+2) = 0, 2x+1 = 0, X = -1/2. -x+2 = 0, X = 2.
X-intercepts: (-1/2,0), (2,0).
B. Since the coefficient of x^2 is negative, the parabola opens downward. Therefore, the vertex is a maximum.
Locate the vertex: h = Xv = -B/2A = -24/-32 = 3/4, Plug 3/4 into the given Eq to find k(Yv). K = -16(3/4)^2 + 16(3/4) + 16 = 19. V(h,k) = V(3/4,19).
C. Choose 3 points above and below the vertex for graphing. Include the points calculated in part A which shows where the graph crosses the x-axis.
Answer:
Your original answer is corrrect
Step-by-step explanation:
At X= -1, Y decreases and then it rises back to -1 and continues to increase
