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3 years ago

7

Your parents are ordering your school pictures. They order one 8 × 10 (8 inches by 10 inches), two 5 × 7's, and 8 wallet size (2

.5 inches by 3.25 inches). Which of the pictures are similar in dimension?

2 answers:

Dvinal [7]3 years ago

6 0

The 8x10 and 2.5x3.25 are closest in ratio.

Ksenya-84 [330]3 years ago

3 0

Answer:

Step-by-step explanation: its 5X7

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Maria is buying new carpet. Her bedroom is in the shape of a square and the length id each side is 12 feet. Write and simplify a

satela [25.4K]

Answer: She needed 144 square feet of carpet.

Step-by-step explanation:

Given : Maria is buying new carpet. Her bedroom is in the shape of a square.

The length of each side is 12 feet.

We know that the area of square = $(side)^2$

So , the area of the bedroom = $(12)^2$ [which is an exponential expression]

Simplify it

The area of the bedroom = $12\times12=144\ \text{ft}^2$

Also, the carpet she needed = Area of the bedroom.

Thus , She needed 144 square feet of carpet.

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4.0681 to the nearest thousand

Neporo4naja [7]

4.068 is the answer to it

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2 years ago

Enter the exact product of 5.21 •7.3.

frez [133]

Answer:

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Step-by-step explanation:

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3 years ago

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(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0

Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

$P(A)+P(B)+P(A\cap B)=P(A\cup B)$

We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

$0.4+0.7-P(A\cap B)\geq 0.7$

$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

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3 years ago

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melamori03 [73]

Answer:

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Step-by-step explanation:

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2 years ago

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