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3 years ago

how do you find equivalent ratos if one ratio is given and they ask you to figure what are the other ratios which are equivalent

1 answer:

3 0

Example: Given 3/14, we could obtain equivalent ratios by mult. 3/14 by 2/2, 100/100, 1385/1385, etc. So long as you mult. both 3 and 14 by the same quantity, the new ratio will equal the old.

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A house was bought for £100,000

jolli1 [7]

Answer:

122500

Step-by-step explanation:

The formula

A=p(1+rt)

A ?

P 100000

R 0.075

T 3 years

A=100,000×(1+0.075×3)

A=122500

5 0

3 years ago

Which algebraic expression has a term with a coefficient of 9? O A. 6(x + 5) O B. 6x - 9 O C. 6+ x - 9 O D. 9x=6

Dimas [21]

Answer:

D is the answer to your question

7 0

3 years ago

Solve by elimination: 2x + 4y = 34 x+4y = 27 A (7,-5) B (6,6) (7,5) (5,7)

julsineya [31]

Answer:

(7,5)

Step-by-step explanation:

{2x + 4y = 34

{4y = 27 - x

2x + 27 - x = 34

x=7

4y = 27 - 7

y = 5 so the answer is ( 7,5)

3 0

3 years ago

Read 2 more answers

What is the HCF of 20 36 and 45??

tangare [24]

20=1×2×2×5=1×4×5

36=1×2×2×9=1×4×9

45=1×3×3×5=1×9×5[/tex]

HCF=1

6 0

3 years ago

Read 2 more answers

A mass weighing 3 lb stretches a spring 3 in. If the mass is pushed upward, contracting the spring a distance of 1 in and then s

Bas_tet [7]

Answer:

Step-by-step explanation:

$m=\frac{3}{32}\\ \gamma =0\text{ damping constant.}\\ k=\frac{3}{\frac{1}{4}}=12\\ F(t)=0\\ \text{so equation of motion is }\\ mu''+\gamma u'+ku=F(t)\\ \frac{3u''}{32}+12u=0\\ u''+128u=0\\ \text{and initial conditions are}\\ u(0)=-\frac{1}{12}\\ u'(0)=2\\ u''+128u=0\\ \text{characterstic equation is}\\ r^2+128=0\\ \text{roots are }\\ r=\pm 8\sqrt{2}i\\ \text{therefore general solution is}\\ u(t)=A\cos8\sqrt{2}t+Bsin8\sqrt{2}t\\ \text{using initial conditions we get}\\ A=-\frac{1}{12}\\ B=\frac{\sqrt{2}}{8}\\ \text{therefore solution is }\\ u(t)=-\frac{1}{12}\cos8\sqrt{2}t+\frac{\sqrt{2}}{8}\sin8\sqrt{2}t\\
{hence}\\R=\sqrt{\frac{11}{288}}\\\\\sigma=\pi - \tan^{-1}\frac{1}{\sqrt{2}}\\\\\omega_0=8\sqrt{2}\\T=\frac{4}{4\sqrt{2}}$

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3 years ago