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3 years ago

14

What is the difference between a prime number and a complex number?

2 answers:

katrin2010 [14]3 years ago

7 0

A Prime number is a number is a number which cannot be divided by any numbers except for itself and one to give an integer

A Complex Number is any number containing Real and Imaginary parts ( $Imaginary= \sqrt{-1}=i$

mixer [17]3 years ago

6 0

"Prime"and "complex"are not opposites. If a number is a prime, then it has
exactly two factors ... ' 1 ' and itself. If it has any more factors, then it's not
a prime number, it's a "COMPOSITE" number.

<span>(If a number is not a 'complex' number, then it's a REAL number.</span>)

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If a passanger is sellected at random, what is the probability that the passenger was female and survived

Jet001 [13]

??? Depends on how many people are there

3 0

3 years ago

If a snowball melts so that its surface area decreases at a rate of 3 cm2/min, find the rate (in cm/min) at which the diameter d

grin007 [14]

Answer:

The diameter decreases at a rate of 0.053 cm/min.

Step-by-step explanation:

Surface area of an snowball

The surface area of an snowball has the following equation:

$S_{a} = \pi d^2$

In which d is the diameter.

Implicit differentiation:

To solve this question, we differentiate the equation for the surface area implictly, in function of t. So

$\frac{dS_{a}}{dt} = 2d\pi\frac{dd}{dt}$

Surface area decreases at a rate of 3 cm2/min

This means that $\frac{dS_{a}}{dt} = -3$

Tind the rate (in cm/min) at which the diameter decreases when the diameter is 9 cm.

This is $\frac{dd}{dt}$ when $d = 9$ . So

$\frac{dS_{a}}{dt} = 2d\pi\frac{dd}{dt}$

$-3 = 2*9\pi\frac{dd}{dt}$

$\frac{dd}{dt} = -\frac{3}{18\pi}$

$\frac{dd}{dt} = -0.053$

The diameter decreases at a rate of 0.053 cm/min.

7 0

3 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

5 0

3 years ago

Read 2 more answers

Find the distance between the points (1, 5) and (1, -4).

Ganezh [65]

Answer:

9

Step-by-step explanation:

$\tt distance=\sqrt{(1-1)^2+(-4-5)^2}=\sqrt{0^2+9^{2}}=\sqrt{9^2} =9$

6 0

3 years ago

Read 2 more answers

Write the expression in complete factored form. 4c(y+3) - (y+3)=

Anuta_ua [19.1K]

Answer:

(4c-1)(y+3)

Step-by-step explanation:

4c(y+3) -(y+3)

=(4c-1)(y+3)

8 0

3 years ago