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Lapatulllka [165]
3 years ago
9

Write an addition equation with a positive addend and a negative addend and a resulting sum of -8

Mathematics
1 answer:
Airida [17]3 years ago
3 0
There's an infinite number of solutions. here's a few.
1+-9=-8
2+-10=-8
3+-11=-8
4+-12=-8
5+-13=-8
6+-14=-8

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Add or subtract <br> 4-2 3/7
sergeinik [125]

Answer:

subtract

Step-by-step explanation:

6 0
3 years ago
Check if given set of numbers 6,8,10 forms pythagorean triplet or not?​
kipiarov [429]

\LARGE{ \underline{ \tt{Required \: answer:}}}

We know that,

  • Pythagoras theoram is given by : p² + b² = h²

  • In a Pythagoras triplet, the longest side represents the hypotenuse of the triangle.

Then,

We should check that, whether the sum of squares of the smaller sides will be equal to the square of the third side or not. Then, we can determine the above easily.

Sum of squares of smaller sides:

= 6² + 8²

= 36 + 64

= 100

Square of longer side:

= 10²

= 100

Sum of squares of smaller sides = Square of longer side. Hence, 6,8,10 are Pythagorean triplets.

And we are done! :D

⛱️ \large{ \blue{ \bf{FadedElla}}}

6 0
2 years ago
What is the value of minus 6(-2)cubed - 4 squared - 3(-2x4)?
iogann1982 [59]

Find the value of -6(-2)^2 - 4^2 - 3(-2x^4).

-6(-2)^2 - 4^2 - 3(-2x^4)

Multiply -6(-2)^2.

12^2 - 4^2 - 3(-2x^4)

Subtract 12^2 and -4^2.

8 - 3(-2x^4)

Distribute -3(-2x^4).

8 + 6x^4

Therefore the value of 6(-2)^2 - 4^2 - 3(-2x^4) is 8 + 6x^4.

6 0
3 years ago
What is the simplified form of the following expression?
kogti [31]

Answer:

\sqrt{3}


Step-by-step explanation:

We will be using 2 properties of radicals in this simplification (outlined below).

  • \sqrt{a*b}=\sqrt{a}* \sqrt{b}
  • \sqrt{a}*\sqrt{a}=a

<em>Let's simplify this:</em>

2\sqrt{27} +\sqrt{12} -3\sqrt{3}-2\sqrt{12}\\ =2\sqrt{9*3}+\sqrt{4*3} -3\sqrt{3}-2\sqrt{4*3} \\=2\sqrt{9} \sqrt{3} +\sqrt{4} \sqrt{3}-3\sqrt{3}-2\sqrt{4} \sqrt{3} \\=2(3)\sqrt{3}+(2)\sqrt{3} -3\sqrt{3}-2(2)\sqrt{3} \\ =6\sqrt{3} +2\sqrt{3}-3\sqrt{3}-4\sqrt{3}  \\=\sqrt{3}


First answer choice is right.

5 0
3 years ago
Find the general solution of {y}''-3y=8e^{3t}+4sin(t) .
babunello [35]

Answer:

y(x)=C_1e^{\sqrt3t}+C_2e^{-\sqrt3t}-\frac{4}{3}e^{3t}-sint

Step-by-step explanation:

We are given that linear differential equation

y''-3y=8e^{3t}+4 sint

Auxillary equation

D^2-3=0

D=\pm \sqrt3

C.F=C_1e^{\sqrt3t}+C_2e^{-\sqrt3}

P.I=\frac{8e^{3t}+4sin t}{D^2-3}

P.I=\frac{8e^{3t}}{9-3}+4\frac{sint }{-1-3}

P.I=e^{ax}{\phi (D+a)} and P.I=\frac{sinax}{(\phi D)}where D square is replace by - a square

P.I=-\frac{4}{3}e^{3t}- sint

Hence, the general solution

G.S=C.F+P.I

y(x)=C_1e^{\sqrt3t}+C_2e^{-\sqrt3t}-\frac{4}{3}e^{3t}-sint

3 0
3 years ago
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