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n200080 [17]
3 years ago
11

Heather recorded the weight of her cat Sally for the past ten months. She is going to the vet this month. She is predicting that

the cat's weight will be close to the mean of her data. About how much is she predicting that Sally will weigh?

Mathematics
1 answer:
qwelly [4]3 years ago
5 0
  The mean of data is Sally's prediction which is congruent to her cat's weigh:

mean=average weight= (13.5+12.5+10.5+11.2+11.2+10.8+9.5+13.4+11.5+11.8)/10= 11.59 lb is the answer


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dusya [7]

Answer:

\frac{dC}{dQ} \approx 1.25, C(101)-C(100) = 1.247, \delta = 0.24\,\%

Step-by-step explanation:

The marginal cost function is:

\frac{dC}{dQ} = 12.5\cdot x^{-\frac{1}{2} }

The marginal cost for 100 books is:

\frac{dC}{dQ} \approx 1.25

The difference is:

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The relative error is:

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6 0
3 years ago
A basketball coach kept stats for his team in free throw percentage and steals (among others). At the last game, Erin's free thr
Setler79 [48]

Answer:

Due to the higher z-score, she did better in the free throw category.

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

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Free-throws:

Her free throw percentage was 79%, which means that X = 79

The team averaged 87% from the free throw line with a standard deviation of 12, which means that \mu = 87, \sigma = 12. So

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She had 4 steals, which means that X = 4

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Z = \frac{X - \mu}{\sigma}

Z = \frac{4 - 7}{3}

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Due to the higher z-score, she did better in the free throw category.

6 0
3 years ago
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6 0
3 years ago
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