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bazaltina [42]
2 years ago
7

The ordered pair below is a solution to which equation? (2, 12) A.y=1/5x B.y=1/2x C. y = 2x D. y = 6x

Mathematics
2 answers:
Orlov [11]2 years ago
8 0
D. y = 6x...subbing in (2,12)...x = 2 and y = 12
    12 = 6(2)
    12 = 12 (correct)

so (2,12) is a solution to : y = 6x
TEA [102]2 years ago
4 0

Answer:

D. y = 6x

Step-by-step explanation:

In order to conclude which pair is a real solution to one of these equations, we need to evaluate the point in each equation.

Let:

(x,y)=(2,12)

So, this pair will be a solution if when evaluating the value of x=2 in the function the result is y=12.

<em>For A.</em>

y(x)=\frac{1}{5}x \\\\y(2)=\frac{2}{5} =0.4\neq12

This pair is not a solution to this equation.

<em>For B.</em>

<em></em>

y(x)=\frac{1}{2}x\\\\y(2)=\frac{2}{2} =1 \neq 12

This pair is not a solution to this equation.

<em>For C.</em>

y(x)=2x\\\\y(2)=2*2=4 \neq 12

This pair is not a solution to this equation.

<em>For D.</em>

y(x)=6x\\\\y(2)=6*2=12

<em><u>This pair is a solution to this equation.</u></em>

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$13,957 is invested, part at 7% and the rest at 6%. If the interest earned from the amount invested at 7% exceeds the interest e
ch4aika [34]

Answer:

The Amount invested at 7% interest is $12,855

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Step-by-step explanation:

Given as :

The Total money invested = $13,957

Let The money invested at 7% = p_1  = $A

And The money invested at 6% = p_2 = $13957 - $A

Let The interest earn at 7% = I_1

And The interest earn at 6% = I_2

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Let The time period = 1 year

Now,<u> From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}

Or,  I_1 = \dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}

Or,  I_1 = \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}

And

I_2 = \dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}

Or,  I_2 = \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}

∵  I_1 -  I_2 = $833.73

So, \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100} -  \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100} = $833.73

Or, 7 A - 6 (13,957 - A) = $833.73 × 100

Or, 7 A - $83,742 + 6 A = $83373

Or, 13 A = $83373 + $83742

Or, 13 A = $167,115

∴ A = \dfrac{167115}{13}

i.e A = $12,855

So, The Amount invested at 7% interest = A = $12,855

And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855

I.e The Amount invested at 6% interest = $1,102

Hence,The Amount invested at 7% interest is $12,855

And The Amount invested at 6% interest = $1,102   . Answer

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