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bazaltina [42]
3 years ago
7

The ordered pair below is a solution to which equation? (2, 12) A.y=1/5x B.y=1/2x C. y = 2x D. y = 6x

Mathematics
2 answers:
Orlov [11]3 years ago
8 0
D. y = 6x...subbing in (2,12)...x = 2 and y = 12
    12 = 6(2)
    12 = 12 (correct)

so (2,12) is a solution to : y = 6x
TEA [102]3 years ago
4 0

Answer:

D. y = 6x

Step-by-step explanation:

In order to conclude which pair is a real solution to one of these equations, we need to evaluate the point in each equation.

Let:

(x,y)=(2,12)

So, this pair will be a solution if when evaluating the value of x=2 in the function the result is y=12.

<em>For A.</em>

y(x)=\frac{1}{5}x \\\\y(2)=\frac{2}{5} =0.4\neq12

This pair is not a solution to this equation.

<em>For B.</em>

<em></em>

y(x)=\frac{1}{2}x\\\\y(2)=\frac{2}{2} =1 \neq 12

This pair is not a solution to this equation.

<em>For C.</em>

y(x)=2x\\\\y(2)=2*2=4 \neq 12

This pair is not a solution to this equation.

<em>For D.</em>

y(x)=6x\\\\y(2)=6*2=12

<em><u>This pair is a solution to this equation.</u></em>

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We can use the quadratic formula to find t

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       ----------------------

          2a

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       ----------------------

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       ----------------------

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       ----------------------

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t = 15+ sqrt(9121)                       t = 15- sqrt(9121)

     --------------------   or                    -------------------  

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