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bazaltina [42]
3 years ago
7

The ordered pair below is a solution to which equation? (2, 12) A.y=1/5x B.y=1/2x C. y = 2x D. y = 6x

Mathematics
2 answers:
Orlov [11]3 years ago
8 0
D. y = 6x...subbing in (2,12)...x = 2 and y = 12
    12 = 6(2)
    12 = 12 (correct)

so (2,12) is a solution to : y = 6x
TEA [102]3 years ago
4 0

Answer:

D. y = 6x

Step-by-step explanation:

In order to conclude which pair is a real solution to one of these equations, we need to evaluate the point in each equation.

Let:

(x,y)=(2,12)

So, this pair will be a solution if when evaluating the value of x=2 in the function the result is y=12.

<em>For A.</em>

y(x)=\frac{1}{5}x \\\\y(2)=\frac{2}{5} =0.4\neq12

This pair is not a solution to this equation.

<em>For B.</em>

<em></em>

y(x)=\frac{1}{2}x\\\\y(2)=\frac{2}{2} =1 \neq 12

This pair is not a solution to this equation.

<em>For C.</em>

y(x)=2x\\\\y(2)=2*2=4 \neq 12

This pair is not a solution to this equation.

<em>For D.</em>

y(x)=6x\\\\y(2)=6*2=12

<em><u>This pair is a solution to this equation.</u></em>

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f_X(x)=\dbinom nxp^x(1-p)^{n-x}

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

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You can similarly derive the variance by computing \mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2, but I'll leave that as an exercise for you. You would find that \mathbb V(X)=np(1-p), so the variance here would be

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<h3><u>QU</u><u>ESTION</u><u>:</u></h3>

WHAT IS THE PRODUCT OF: 7.21 x 4.2

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<h3>SOLUTION AND ANSWER:</h3>

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NOTE: Kindly see this answer from brainly app if you are in web to see the displayed formats here.

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