Answer:
a)
#include <iostream>
using namespace std;
int main() {
bool a,b,c;
cin>>a>>b;
if(a^b)//X-OR operator in C++.
c=true;
else
c=false;
cout<<c;
return 0;
}
b)
#include <iostream>
using namespace std;
int main() {
bool a,b,c,d;
cin>>a>>b>>c;
if((a^b)^c)//X-OR operator in C++.
d=true;
else
d=false;
cout<<d;
return 0;
}
Explanation:
The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.
In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.
Answer:
setTimeout is a native JavaScript function (although it can be used with a library such as jQuery, as we'll see later on), which calls a function or executes a code snippet after a specified delay (in milliseconds).
Answer:
She should join the Future Business Leaders of America–Phi Beta Lambda
Explanation:
CTSOs are Career and technical student organizations. These organizations are vocational and extracurricular groups based primarily in high schools, colleges and career technological centres, for students in Career and Technical Education. They are important parts of the high school and college programs.
The Future Business Leaders of America–Phi Beta Lambda prepares students to become community-minded business leaders. It provides opportunities to learn career skills and gain leadership experience.
Therefore Adele should pick this CTSO
Solution:
initial = float(eval(input('Enter the monthly saving amount: ')))
x = (1 + 0.00417)
month_one = initial * x
month_two = (initial + month_one) * x
month_three = (initial + month_two) * x
month_four = (initial + month_three) * x
month_five = (initial + month_four) * x
month_six = (initial + month_five) * x
print('The sixth month value is: '+str(month_six))
Don't forget the saving amount, and initialize the balance with that amount. Inside the loop, work out and add the interest and then add the saving amount for the next month.
balance = 801
for month in range(6):
balance = balance * (1.00417)
print(balance)
Answer:
see below
Explanation:
The program of interest is the function "findMode[x, n]" in the attached. It is written the Wolfram Language of Mathematica.
The basic idea is that the data in the array is sorted. The sorted array is partitioned into sets of identical elements, and the number in each of those sets is counted. The maximum of those counts is the mode. The location of the maximum count corresponds to the location of the set having that count. We use that location information to pull out the mode value(s).
If there is more than one mode, all are reported.
__
An example data array is provided, along with the program output.
