A generic odd number can be written as
Since there is an odd number every two numbers, three consecutive odd numbers will be
Now let's make up the equations: the sum of the first two is
And 27 less than 3 times the largest is
These two must be the same, so we have
Subtracting 4k and 3 from both sides gives
Which means that the problem has no solution.
To confirm this hypothesis, we can observe that, on the left hand side, we have the sum of two odd numbers, which is even
On the right hand side, we have an odd number, multiplied by 3 (still odd), take away 27 (still odd).
So, the left hand side is even, and the right hand side is odd. They can't be the same number.
Is this a trick question? They're both a pound.
Answer:
D=24
Step-by-step explanation:
y inversely as x
x=k/y
By cross multiplication
k=xy
k=12*6
k=72
finding y
72=3y
y=24
Answer: The range is y ≥ 3.
Step-by-step explanation:
When we have an equation:
y = f(x)
The range is the set of the possible values of y.
In this case, we have:
y = f(x) = 2*x^2 - 20*x + 53
This is a quadratic equation, and the leading coefficient is positive. This means that the arms of the graph will open upwards.
Then the minimum value of y will be the vale at the vertex.
We know that for a quadratic equation of the form:
a*x^2 + b*x + c
The vertex is at:
x = -b/2a
Then in this case, the vertex will be at:
x = -(-20)/(2*2) = 20/4 = 5
Then the smallest value of this function will be:
f(5) = 2*5^2 - 20*5 + 53 = 3
This is the smallest value that y can take, and y can take any value greater than 3.
Then the range can be written as:
y ≥ 3.
