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dangina [55]
3 years ago
13

The top and bottom margins of a poster are each 15 cm and the side margins are each 10 cm. If the area of printed material on th

e poster is fixed at 2400 cm2, find the dimensions of the poster with the smallest area.--------- cm (width)--------- cm (height)
Mathematics
1 answer:
kap26 [50]3 years ago
6 0

Answer:

Step-by-step explanation:

let the sides be x and y

x y=2400

y=\frac{2400}{x}\\new~ dimensions ~are ~x+30~and~y+20\\area~A=(x+30)(y+20)\\=xy+20x+30y+600\\=2400+600+20x+30*\frac{2400}{x}\\=3000+20x+\frac{72000}{x}\\\frac{dA}{dx}=20-\frac{72000}{x^2}\\\frac{dA}{dx}=0~gives\\20 x^2=72000\\x^2=3600\\x=\sqrt{3600} =60\\\frac{d^2A}{dx^2}=\frac{144000}{x^3}>0~at ~x=60\\y=\frac{2400}{60}=40\\

so A is minimum when x=60

y=40 cm

so dimensions are 60+30=90 cm

and 40+20=60 cm

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