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4 years ago

what is the area in square centimeters of the trapezoid below the height is 6.4 and the base is 12.9 and 8.6

Mathematics

2 answers:

Leona [35]4 years ago

4 0

Hello!
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The area in square centimeters is 68.8.
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Have a great day!

Lelu [443]4 years ago

3 0

Answer:

The area of given trapezoid is 68.8 cm²

Step-by-step explanation:

Given: A trapezoid with height 6.4 cm and parallel base is 12.9 cm and 8.6 cm.

We have to find the area of area of this trapezoid.

Area of trapezoid = $\frac{1}{2}\times \text{sum of parallel sides}\times height$

Given : Height = 6.4 cm

and parallel base is 12.9 cm and 8.6 cm.

Substitute, we have,

Area of trapezoid = $\frac{1}{2}\times (12.9+8.6)\times 6.4$

Simplify, we have,

Area of trapezoid = $\frac{1}{2}\times 21.5\times 6.4$

Area of trapezoid = 68.8 cm²

Thus, The area of given trapezoid is 68.8 cm²

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3 years ago

If line n bisects segment CE, find the positive value of x. A.6 B.10 C.15 D.9

givi [52]

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Answer:

D. 9

Step-by-step explanation:

The segment lengths are equal, so ...

x^2 = 90-x

x^2 +x -90 = 0 . . . . . . add x-90 to put in standard form

(x +10)(x -9) = 0 . . . . . factor

The solutions are the values of x that make the factors zero: -10, 9.

The positive value of x is 9.

8 0

3 years ago

Read 2 more answers

Sabiendo que cada persona unos 4 500 000 glóbulos rojos por milímetro cúbico y que su cantidad de sangre es de 5 litros A) Que l

love history [14]

Answer:

Part A) distance covered by the aligned red cells is: 180000 Km

Part B) 8000000 bacteria (8 million bacteria)

Step-by-step explanation:

Part A)

Let's first find the total number of red cells that the person has in the 5 liters, knowing that there are 4,500,000 of them in a cubic millimetre:

Since 1 liter contains 1,000,000 cubic millimetres, then, in 5 liters there must be 5 times that number of cubic millimetres. That is a total of 5,000,000 cubic millimetres.

Since in each cubic millimetre there are 4,500,000 red cells, then the number of red cells in the 5 liters must be the product of these two quantities:

4,500,000 x 5,000,000 = 22,500,000,000,000 red blood cells.

Now, to find the distance they will cover aligned one after the other, knowing that their average diameter is 0.008 mm is:

22,500,000,000,000 x 0.008 mm= 180000000000 mm

$22.5\,\,10^{12} * 8\,\,10^{-3}=1.8\,\,10^{11}$ mm

In order to convert this distance into Km as requested, we use the fact that 1 mm = 0.000001 Km, or using exponents in base ten:

1 mm = $10^{-6}\,\,Km$

Then, the distance covered in kilometers is:

$1.8\,\,10^{11}\,*\,10^{-6} \,\,Km=1.8\,\,10^{5}\,\,Km=180000\,\,Km$

Part B)

The vaccine contains a total of $10^8$ bacteria per $cm^3$

In order to find how many bacteria we have in 80 $mm^3$ of the vaccine, we first need to convert 80 $mm^3$ into $cm^3$ :

$80\,\, mm^3 = 0.08 \,\,cm^3$

Then, if in one $cm^3$ there is $10^8$ bacteria, in $0.08\,\,cm^3$ there would be: $0.08\,*\,10^8$ bacteria. That is: $8\,\,10^6$ bacteria = 8000000 bacteria (eight million bacteria)