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melisa1 [442]
3 years ago
10

A triangle has one angle that measures 32 degrees, one angle that measures 50 degrees, and one angle that measures 98 degrees. W

hat kind of triangle is it?
Mathematics
2 answers:
horrorfan [7]3 years ago
6 0
Obtuse scalene triangle
Ilya [14]3 years ago
5 0
First, let's check.
32 + 50 + 98 = 180
The angle measures do add up to 180, so such a triangle can exist.

Since it has an obtuse angle, the 98-deg angle, it is a obtuse triangle.
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Hexadecimal numerals are widely used by computer system designers and programmers, as they provide a human-friendly representation of binary-coded values. Each hexadecimal digit represents four binary digits, also known as a nibble, which is half a byte.
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3 years ago
Two angles are supplementary angles. One angle measures 58 degrees. The other angle measures 3n + 5 degrees. What is the value o
stepladder [879]

Answer:

39

Step-by-step explanation:

Angles are supplementary when they add up to 180.  So, we know the other angle that isn't 58 is 180-58=122.  Therefore, 122=3n+5\\3n=117\\n=39

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3 years ago
Which one is greater 7 pounds or 70 ounces
eimsori [14]

Answer:

7 pounds is greater

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8 0
2 years ago
Read 2 more answers
HELP ME ASAP!!! PLEASE
Sloan [31]
B, 190.
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4 0
3 years ago
Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers
Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the x^2 coefficient is 1, i.e. the equation is written like x^2+bx+c=0, then you can say the following about the coefficients b and c:

  • b is the opposite of the sum of the roots
  • c is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

  • 4+(-2) = 4-2 = 2 \implies b = -2
  • 4 \cdot (-2) = -8 \implies c = -8

So, the equation is x^2-2x-8=0

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

  • \dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}
  • \dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}

And so the equation is

x^2 - \dfrac{5}{4} + \dfrac{3}{8} = 0

In order to have integer coefficients, you can multiply both sides of the equation by 8:

8x^2 - 10 + 3 = 0

5 0
3 years ago
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