Answer:
and
.
Step-by-step explanation:
So I believe the problem is this:

where we are asked to find values for
and
such that the equation holds for any
in the equation's domain.
So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).
In other words this will clear the fractions.


As you can see there was some cancellation.
I'm going to plug in -7 for x because x+7 becomes 0 then.




Divide both sides by -10:


Now we have:
with 
I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.




Divide both sides by 10:


So
and
.
X^2 - 25 is a difference of squares which has a special factorization.
In general, a^2 - b^2 = (a + b)(a - b)
x^2 - 25 = 0
(x + 5)(x - 5) = 0
x + 5 = 0 or x - 5 = 0
x = -5 or x = 5
Answer:
That's incorrect. The simplest way to show this is by evaluating the functions at a given point. Let's say x=0, then:
Sin(-x) = Sin(0) = 0
-cos x = -cos (0) = -1
Therefore, Sin(-x)≠-cos x.
Answer: it is 1.8
Step-by-step explanation: you can look up this same qustion and find it on branly <3 your right