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anygoal [31]
3 years ago
13

Help me pls guys/girls

Mathematics
1 answer:
Kamila [148]3 years ago
5 0

Answer:

 V = 9.828 * 10^7 mm^3

a= 9.828  b = 7

9,827,000  mm^3

Step-by-step explanation:

The volume of a rectangular prism is

V = l*w*h

V = 1.2 *10^3  * 3.9*10^2  * 2.1*10^2

We multiply the numbers out front and add the exponents  (the powers of 10)

V = (1.2*3.9*2.1)  * 10^(3+2+2)

 V = 9.828 * 10^7 mm^3

Rewriting this in standard form means moving the decimal 7 places to the left.  Since there is not enough places add zeros

9,827,000  mm^3

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Sarah needs 30 liters of a 25% acid solution how many liters of the 10% and the 30% acid solutions should she mix to get what sh
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Answer:

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Step-by-step explanation:

Volume of 10% solution plus volume of 30% solution = total volume of 25% volume.

x + y = 30

Acid in 10% solution plus acid in 30% solution = total acid in 25% solution.

0.10 x + 0.30 y = 30 × 0.25

0.10 x + 0.30 y = 7.5

Solve the system of equations, using either substitution or elimination.  I'll use substitution:

x = 30 − y

0.10 (30 − y) + 0.30 y = 7.5

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ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

7 0
3 years ago
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