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3 years ago

12.......................

Mathematics

1 answer:

Nadusha1986 [10]3 years ago

3 0

Answer:

A rational exponent is an exponent that is a fraction. If the fraction has an even denominator, the root will be of an even number (like the square root, the 4th root, etc.). Think about it when you square something: -2 • -2 = 4, 2 • 2 = 4. No matter the sign, any number multiplied by itself an even number of times will make a positive number. So, you can't take the square root of a negative number because it is impossible to get a negative number when squaring! This applies to ALL even roots/exponents. So, (-1)^½ does not exist! Look: (-1)^½ becomes √(-1) which is an imaginary number!

Step-by-step explanation:

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What is the range of the function f(x)=3/4x-3

kipiarov [429]

Answer:

(-∞,0)∪(0,∞)

Step-by-step explanation:

The domain of a function is wherever the y values exist. The only time the y values dont exist in this function is when the denominator is zero. So the denominator does not exist at x=0, because that is when 4x = 0.

7 0

3 years ago

1. You go to the local Sport Grill for quarter wings day.

DedPeter [7]

Answer:

If the 20% discount is by the hour then the answer would be $11.70 I think.

0.25x78= 19.50

19.50x0.20(20%)= 3.90

19.50-3.90-3.90= 11.70

Hope this helps!

Step-by-step explanation:

8 0

3 years ago

How do I solve a given right triangle to find Cos, Sin, and Tan. How do I solve for a missing adjacent side? (For Example: Imagi

Sphinxa [80]

The steps to find cos, sin, and tan and missing adjacent side of a given right angle triangle is explained.

<u>Solution:</u>

Given, a right triangle with A, B, and C.

Opposite side = 70 inches

Hypotenuse = 12 feet = 12 $\times$ 12 inches = 144 inches

Adjacent side = "x" inches.

We are not given angle, so we have to use the hypotenuse theorem

Hypotenuse theorem means square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.

$\text { hypotenuse }^{2}=(\text { opposite side })^{2}+(\text { adjacent side })^{2}$

Substituting the values we get,

$\begin{array}{l}{\rightarrow 144^{2}=70^{2}+x^{2}} \\\\ {\rightarrow x^{2}=20736-4900} \\\\ {\rightarrow x^{2}=15836} \\\\ {\rightarrow x=\sqrt{15836}} \\\\ {\rightarrow x=125.841}\end{array}$

So, the adjacent side value is 125.8 inches approximately.

Hence the steps to find adjacent side is shown above

Now let us find cos, sin and tan

$\begin{aligned} \sin \theta &=\frac{\text {opposite side}}{\text {hypotenuse}} \\\\ \cos \theta &=\frac{\text {adjacent side}}{\text {hypotenuse}} \\\\ \tan \theta &=\frac{\text {opposite side}}{\text {adjacent side}} \end{aligned}$

By substituting the required values, we can find cos, sin and tan

$\begin{array}{l}{\sin \theta=\frac{70}{144}=\frac{35}{122}} \\\\ {\cos \theta=\frac{125.8}{144}=\frac{62.9}{122}} \\\\ {\tan \theta=\frac{70}{125.8}=\frac{35}{62.9}}\end{array}$

5 0

3 years ago

Find the z-score boundaries that separate a normal distribution as described in each of the following. a. The middle 20% from th

Anna007 [38]

Answer:

a) The boundaries are $Z = \pm 0.253$

b) The boundaries are $Z = \pm 0.675$ .

c) The boundaries are $Z = \pm 1.96$ .

d) The boundaries are $Z = \pm 2.575$ .

Step-by-step explanation:

Z-score:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

a. The middle 20% from the 80% in the tails.

The middle 20% is between the 50 - (20/2) = 40th percentile and the 50 + (20/2) = 60th percentile:

40th percentile: Z has a pvalue of 0.4, so Z = -0.253.

60th percentile: Z has a pvalue of 0.6, so Z = 0.253.

The boundaries are $Z = \pm 0.253$ .

b. The middle 50% from the 50% in the tails.

The middle 50% is between the 50 - (50/2) = 25th percentile and the 50 + (50/2) = 75th percentile:

25th percentile: Z has a pvalue of 0.25, so Z = -0.675.

75th percentile: Z has a pvalue of 0.75, so Z = 0.675.

The boundaries are $Z = \pm 0.675$ .

c. The middle 95% from the 5% in the tails.

The middle 95% is between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile:

2.5th percentile: Z has a pvalue of 0.025, so Z = -1.96.

97.5th percentile: Z has a pvalue of 0.975, so Z = 1.96.

The boundaries are $Z = \pm 1.96$ .

d. The middle 99% from the 1% in the tails.

The middle 99% is between the 50 - (99/2) = 0.5th percentile and the 50 + (99/2) = 99.5th percentile:

0.5th percentile: Z has a pvalue of 0.005, so Z = -2.575.

99.5th percentile: Z has a pvalue of 0.995, so Z = 2.575.

The boundaries are $Z = \pm 2.575$ .

6 0

3 years ago

Jakob is working on his math homework. He decides that the sum of two rational numbers is

xeze [42]

Answer:

yes because rational numbers are rational. they stay the same

Step-by-step explanation:

7 0

3 years ago