All categories

3 years ago

A boy weighs 31.5 kilograms. how much does he weigh in pounds? use the following conversion: 1 kilogram is 2.2 pounds

Mathematics

2 answers:

ipn [44]3 years ago

7 0

Answer: The required weight of the boy in pounds is 69.3 pounds.

Step-by-step explanation: Given that a boy weighs 31.5 kilograms.

We are to find the weight of the boy in pounds.

Also, given that 1 kilogram = 2.2 pounds.

According to the given information, we have

the weight of the boy = 31.5 kilograms.

Therefore, the weight of the boy in pounds is given by

$31.5\times 2.2=69.3.$

Thus, the required weight of the boy in pounds is 69.3 pounds.

mario62 [17]3 years ago

4 0

If 1 kilogram equals 2.2 pounds, how many pounds will 31.5 kilograms equal?
31.5*2.2 or 69.3 pounds.

You might be interested in

Which of the expressions are equivalent to the one below 5 x (8+3)

tatuchka [14]

The answer would be 55

5 0

3 years ago

PLEASE DIE TODAY I NEED MY GRADE UP it is not 12.5 this is my last attempt I think 15 points

Volgvan

Answer:

25%

Step-by-step explanation:

1/2 ×1/2

=1/4

=0.25

which is 25%

7 0

3 years ago

4. Combine Like terms: -7(2 + 3x) + (-3x)(-5) + 9* -7x + 5 0 -7X-5 O 7x-5 O 7x + 5

Dima020 [189]

Answer:

-69x-9

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Notice that the alternative hypothesis is a two-tailed test. Suppose ttest_ind method from scipy module is used to perform the t

Korvikt [17]

Answer:

The p-value of the test is 0.0512.

Step-by-step explanation:

The p-value of a test is well-defined as per the probability, [under the null hypothesis (H₀)], of attaining a result equivalent to or more extreme than what was the truly observed value of the test statistic.

In this case the output of the t-test_ind method from scipy module is provided as follows:

Output = (-1.99, 0.0512)

The first value within the parentheses is the test statistic value.

So the test statistic value is, -1.99.

And the second value within the parentheses is the p-value of the test.

So the p-value of the test is 0.0512.

6 0

3 years ago

An artist cuts 4 squares with side length x ft from the corners of a 12 ft-by-18 ft rectangular piece of sheet metal. She bends

Kruka [31]

Answer:

$V=4x^3-60x^2+216x$

Step-by-step explanation:

Volume And Function s

Geometry can usually be joined with algebra to express volumes as a function of some variable. The volume of a parallelepiped of dimensions a,b,c is

$V=abc$

Our problem consists in computing the volume of a box made with some sheet of metal 12 ft by 18 ft. The four corners are cut by a square distance x as shown in the image below .

If the four corners are to be lifted and a box formed, the base of the box will have dimensions (12-2x)(18-2x) and the height will be x. The volume of the box is

$V=x(12-2x)(18-2x)$

Operating and simplifying

$V=4x^3-60x^2+216x$

8 0

3 years ago