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solong [7]
3 years ago
8

A boy weighs 31.5 kilograms. how much does he weigh in pounds? use the following conversion: 1 kilogram is 2.2 pounds

Mathematics
2 answers:
ipn [44]3 years ago
7 0

Answer:  The required weight of the boy in pounds is 69.3 pounds.  

Step-by-step explanation:  Given that a boy weighs 31.5 kilograms.

We are to find the weight of the boy in pounds.

Also, given that 1 kilogram = 2.2 pounds.

According to the given information, we have

the weight of the boy = 31.5 kilograms.

Therefore, the weight of the boy in pounds is given by

31.5\times 2.2=69.3.

Thus, the required weight of the boy in pounds is 69.3 pounds.  

mario62 [17]3 years ago
4 0
If 1 kilogram equals 2.2 pounds, how many pounds will 31.5 kilograms equal?
31.5*2.2 or 69.3 pounds.
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Kobotan [32]

The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid (R) on the X-axis?</h3>

If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

From the given graph:

The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

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here:

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Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8)  from the graph, we have:

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Now, our region bounded by the three lines are:

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Similarly, the change in polar coordinates is:

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where;

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Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

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Step-by-step explanation:

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