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3 years ago

Please help me do this problem. 20 points to the first one that helps me with these 2. I am very desperate.

Mathematics

1 answer:

MAVERICK [17]3 years ago

4 0

Answer:

here's your answer:

Triangle ABC has vertices A(0,0), B(0,4), and C(3,0). Write the equation for the line containing altitude AR in standard...

brainly.com/question/8243985?utm_source=android&utm_medium=share&utm_campaign=question

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Union City Bakery uses a chocolate chip muffin recipe that yields 1/2 cup of milk for every batch of 12 chocolate chip muffins.

nikitadnepr [17]

Answer:

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Step-by-step explanation:

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3 years ago

Graph h(x) = (x - 2)(x - 4)

Sidana [21]

Answer: 8

Step-by-step explanation:

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3 years ago

A rectangle has a height of 4w^3 and a width of 5w^2-3w-4.

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

Area of the entire rectangle = height * width

= 4w³ *( 5w²-3w-4)

= 4w³ * 5w²- 4w³ *3w - 4w³ *4

=20w⁵ - 12w⁴ - 16w³

6 0

3 years ago

Read 2 more answers

A driving distance is 650km. The distance shown on a map is 4 cm. Express the map scale in words.

Anna007 [38]

650 kilometers divided by 4 centimeters. / 650 ÷ 4 (for your answer).

4 0

3 years ago

The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1

Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = $791.28\ mm^3/hr$

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let $r$ represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

$\frac{dr}{dt}=7\ mm/hr$

Volume of cylinder is given by:

$V=\pi\ r^2h$

Finding derivative of the Volume with respect to time.

$\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}$

Plugging in the values given:

$\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)$

$\frac{dV}{dt}=252\pi$

Using $\pi=3.14$

$\frac{dV}{dt}=252(3.14)$

$\frac{dV}{dt}=791.28\ mm^3/hr$ (Answer)

Thus rate of change of the volume of the cylinder at that instant = $791.28\ mm^3/hr$

6 0

3 years ago