Answer:
Step-by-step explanation:
Joint variations occurs when one variable depends on the value of two or more variables. The variable varies directly or indirectly with the other variables combined together. The other variables are held constant. From the given examples, the equation(s) that represent joint variations are
1) z = 3x/y
z varies directly with x and inversely with y.
2) w = abc/4
w varies inversely with a,b and c. 4 is the value of the constant of variation.
Answer:
A and B are functions
Step-by-step explanation:
for A, none of the x's repeat which makes it a FUNCTION
for B, when it starts with x^2, it will always be a FUNCTION (its a quadratic)
for C, 10 repeats for the x so it is NOT A FUNCTION
Answer:
y-2 = 3/10(x+3)
Step-by-step explanation:
3y = 10
y = 10/3
looking for perpendicular so slope = 3/10
using the given point
y-2 = 3/10(x+3)
Answer:
a) No. t < 0 is not part of the useful domain of the function
b) 2.0 seconds
Step-by-step explanation:
a) A graph of the function is shown below. It shows t-intercepts at t=-0.25 and t=2.0. We presume that t is measured forward from some event such as the ball being thrown or hit. The model's predicted ball location has no meaning prior to that event, when values of t are negative.
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b) It is convenient to use a graphing calculator to find the t-intercepts. Or, the equation can be solved for h=0 any of several ways algebraically. One is by factoring.
h = 0 = -16t² +28t +8 . . . . . . . . . . . . the ball hits the ground when h = 0
0 = -4(4t² -7t -2) = -4(4t +1)(t -2)
This has t-intercepts where the factors are zero, at t=-1/4 and t=2.
The ball will hit the ground after 2 seconds.