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3 years ago

Please answer thisss <3

Mathematics

1 answer:

lawyer [7]3 years ago

5 0

Answer:

i think . it is c

Step-by-step explanation:

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bonnie runs 1 2/3 times as far as john each day if bonnie runs 5 miles on monday 3 1/2 miles on tuesday and 5 3/4 miles on wedne

nignag [31]

Answer:

3 miles on Monday

2¹/₁₀ miles on Tuesday

3⁹/₂₀ miles on Wednesday

Step-by-step explanation:

We are told that Bonnie runs 1⅔ (⁵/₃) times as far as John each day

This means that John runs ³/₅ times as far as Bonnie.

MONDAY:

Bonnie runs 5 miles on Monday, therefore, John runs:

³/₅ * 5 = 3 miles

TUESDAY:

Bonnie runs 3½ (⁷/₂) miles on Tuesday, therefore, John runs:

³/₅ * ⁷/₂ = ²¹/₁₀ = 2¹/₁₀ miles

WEDNESDAY:

Bonnie runs 5³/₄ (²³/₄) miles on Wednesday, therefore, John runs:

³/₅ * ²³/₄ = ⁶⁹/₂₀ = 3⁹/₂₀ miles

6 0

3 years ago

1 and a 1/2 divided by 3/8

Musya8 [376]

$1\frac{1}{2}:\frac{3}{8}=\ \ \ \ | make\ improper\ fractions\\\\
\frac{3}{2}:\frac{3}{8}=\ \ \ \ \ \ | multiply\ first\ factor\ by\ inverse\ of\ the\ second\\\\
\frac{3}{2}*\frac{8}{3}=\frac{3*8}{2*3}=\frac{8}{2}=4$

5 0

3 years ago

Read 2 more answers

Divide (18x^3 + 12x – 3x) ÷ 6x^2

andre [41]

First let's simplify it

$\frac{18x^3 + 9x}{6x^2}$

Now let's factor it
$\frac{9x(2x^2 + 1)}{6x^2}$

Lastly, let's simplify
$\frac{3(2x^2 + 1)}{2x}$

4 0

3 years ago

For the inverse variation equation xy=k, what is the constant of variation,k, when x = -3and y=-2

const2013 [10]

Answer:

Step-by-step explanation:

xy=k

Value of k ; when ; x = - 3 and y = - 2

Put x = - 3 and y = - 2 into the equation :

(-3)(-2) = k

-3 * - 2 = k

6 = k

The constant of variation k = 6

8 0

3 years ago

A magazine currently has 8700 subscribers for its online web version. It is adding members at the rate of R(t) = 190e0.03t subsc

aleksklad [387]

Number of subscriber the magazine will have after 3 years from now approximately be 8767

<u>Solution:</u>

Given that magazine currently has 8700 subscribers for its online web version

$\begin{array}{l}{\mathrm{R}(\mathrm{t})=190 \mathrm{e}^{0.03 \mathrm{t}} \text { subscribers/month }} \\\\ {\mathrm{S}(\mathrm{t})=\mathrm{e}^{-0.06 \mathrm{t}}}\end{array}$

After 3 years, time(t) = 36 month

Total number of subscribers after 3 years from now :

Substitute "t" = 36

$\begin{array}{l}{\mathrm{R}(36)=190 \mathrm{e}^{0.03 \times(36)}=190 \times(2.944)} \\\\ {\mathrm{R}(36) \approx 560} \\\\ {\mathrm{S}(36)=\mathrm{e}^{-0.06 \times(36)}=0.12}\end{array}$

Subscribers remaining = 0.12 x 560 = 67.2

The magazine currently has 8700 subscribers

Added Subscriber = 8700 + 560 = 9260

Remaining Subscriber = 8700 + 67.2 = 8767.2

Therefore number of subscriber the magazine will have after 3 years from now approximately be 8767

7 0

3 years ago