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aksik [14]
3 years ago
9

Please help! I’m bad at fractions

Mathematics
1 answer:
shusha [124]3 years ago
7 0

Answer:

i think 2 5/12

Step-by-step explanation:

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What was haley’s function in standard form
Stels [109]

Answer: 7,-10,-2

Step-by-step explanation:

3 0
3 years ago
Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

4 0
3 years ago
Someone please help!!!!!
Mumz [18]
<span>Break down every term into prime factors. ...Look for factors that appear in every single term to determine the GCF. ...Factor the GCF out from every term in front of parentheses, and leave the remnants inside the parentheses. ...<span>Multiply out to simplify each term. </span></span>
5 0
3 years ago
Look at the two expressions.<br><br>3x−18<br><br>3⋅(x−6)<br><br>Are the two expressions equivalent?
Ivanshal [37]
Yes because if you distribute the 3 and multiply it with 3 • x and 3• 6 you’ll get 3x-18
8 0
3 years ago
Read 2 more answers
164,215 rounded to the nearest hundred thousand
ruslelena [56]

The answer is 200,000

3 0
3 years ago
Read 2 more answers
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