3 years ago

Is (0,0) a solution of the system y>x and x+y>0?

1 answer:

8 0

Plug the values (x,y)=(0,0) into the inequalities:

$y\ \textgreater \ x \\
0\ \textgreater \ 0 \\
not \ true \\ \\
x+y\ \textgreater \ 0 \\
0+0\ \textgreater \ 0 \\
0\ \textgreater \ 0 \\
not \ true$

0 isn't greater than 0, no (0,0) is not a solution to either of these inequalities.

The answer is D.

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3 years ago

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VMariaS [17]

Answer:

Second option is the correct answer

$(x+11)^2+(y+6)^2 = 324$

Step-by-step explanation:

$x^{2} +12y+22x+y^2-167=0\\x^{2}+22x +y^2 +12y-167=0\\(x^{2}+22x +121)-121 +(y^2 +12y+36)-36-167=0\\(x+11)^2+(y+6)^2-324 = 0\\\huge\red{\boxed{(x+11)^2+(y+6)^2 = 324}}\\$