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prohojiy [21]
3 years ago
8

Is (0,0) a solution of the system y>x and x+y>0?

Mathematics
1 answer:
olga55 [171]3 years ago
8 0
Plug the values (x,y)=(0,0) into the inequalities:

y\ \textgreater \ x \\
0\ \textgreater \ 0 \\
not \ true \\ \\
x+y\ \textgreater \ 0 \\
0+0\ \textgreater \ 0 \\
0\ \textgreater \ 0 \\
not \ true

0 isn't greater than 0, no (0,0) is not a solution to either of these inequalities.

The answer is D.
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Are you sure this is the COMPLETE problem?

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Keith_Richards [23]

Answer:

a = 100

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Step-by-step explanation:

Just plug this into the equation it shows:

R(1) = (500 + (100)(1)) (50 - (5)(1))

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An arch in the shape of a parabola has a height of 50 feet at the center and a span of 120 feet across. Find the height of the a
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Check the picture below.

so, we know the parabola has a vertex at (0 , 50), we also know it passes through (60 , 0), so then

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\stackrel{vertex}{(0~~,~~50)}\implies y=a(x-0)^2+50\implies y = ax^2+50 \\\\\\ \begin{cases} x =60\\ y = 0 \end{cases}\implies 0=a6^2+50\implies -50=3600a\implies -\cfrac{50}{3600}=a \\\\\\ -\cfrac{1}{72}=a~\hfill therefore~\hfill \boxed{y=-\cfrac{1}{72}x^2+50}

so then, what's "y" when x = 25?

y=-\cfrac{1}{72}25^2+50\implies y = -\cfrac{625}{72}+50\implies y = \cfrac{2975}{72}\implies y\approx 41.32

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Answer:

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Debora [2.8K]

Answer:

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Step-by-step explanation:

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Is this RSM?

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