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ruslelena [56]
2 years ago
15

Which system of equations corresponds to this matrix multiplication operation

Mathematics
2 answers:
dedylja [7]2 years ago
8 0

Answer:

Option B

Step-by-step explanation:

I just completed the test.

faltersainse [42]2 years ago
3 0

Answer:

Option (B)

Step-by-step explanation:

\begin{bmatrix}5 & 2 & 1\\ 7 & -5 & 2\\ -5 & 3 & 1\end{bmatrix}\times \begin{bmatrix}x\\ y\\ z\end{bmatrix}=\begin{bmatrix}16\\ 3\\ 12\end{bmatrix}

By applying multiplication property of the matrices,

\begin{bmatrix}(5x+2y+z)\\ (7x-5y+2z)\\(-5x+3y+z) \end{bmatrix}=\begin{bmatrix}16\\ 3\\ 12\end{bmatrix}

Therefore, system of equations formed will be,

5x + 2y + z = 16

7x - 5y + 2z = 3

-5x + 3y + z = 12

Option (B) will be the correct option.

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Evaluate: 2-^4=<br> A.1/16<br> B.1/8<br> c. -8<br> D.-16
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Answer:

A. 1/16

Step-by-step explanation:

{2}^{ - 4}  =  \frac{1}{ {2}^{4} }  =  \frac{1}{16}  \\

6 0
2 years ago
H=vt+1/2gt^2 solving for G <br>GIVING BRAINLISEST
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Answer:

g=\frac{2h}{t^2}-\frac{2v}{t}

Step-by-step explanation:

So we have the equation:

h=vt+\frac{1}{2}gt^2

And we want to solve for g.

First, isolate g. To do so, subtract vt from both sides:

h-vt=\frac{1}{2}gt^2

Multiply both sides by 2:

2h-2vt=gt^2

Now, divide both sides by t^2:

g=\frac{2h-2vt}{t^2}

Expand:

g=\frac{2h}{t^2}-\frac{2vt}{t^2}

Simplify the second term:

g=\frac{2h}{t^2}-\frac{2v}{t}

And we're done!

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