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ruslelena [56]
3 years ago
15

Which system of equations corresponds to this matrix multiplication operation

Mathematics
2 answers:
dedylja [7]3 years ago
8 0

Answer:

Option B

Step-by-step explanation:

I just completed the test.

faltersainse [42]3 years ago
3 0

Answer:

Option (B)

Step-by-step explanation:

\begin{bmatrix}5 & 2 & 1\\ 7 & -5 & 2\\ -5 & 3 & 1\end{bmatrix}\times \begin{bmatrix}x\\ y\\ z\end{bmatrix}=\begin{bmatrix}16\\ 3\\ 12\end{bmatrix}

By applying multiplication property of the matrices,

\begin{bmatrix}(5x+2y+z)\\ (7x-5y+2z)\\(-5x+3y+z) \end{bmatrix}=\begin{bmatrix}16\\ 3\\ 12\end{bmatrix}

Therefore, system of equations formed will be,

5x + 2y + z = 16

7x - 5y + 2z = 3

-5x + 3y + z = 12

Option (B) will be the correct option.

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Answer:

Is that really the question? Is that the question as your book or teacher wrote down?

Step-by-step explanation:


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13. Find the exact value of sin 30 ° - sin 45 ° cos 45 ° .<br> a. 0 <br> b. 1/2 <br> c. 1 <br> d. 2
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(xsinA-ucosA)^2+(xcosA+ysinA)^2=x^2+y^2​
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Answer:

u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or u = sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) + x tan(A)

Step-by-step explanation:

Solve for u:

(x sin(A) - u cos(A))^2 + (x cos(A) + y sin(A))^2 = x^2 + y^2

Subtract (x cos(A) + y sin(A))^2 from both sides:

(x sin(A) - u cos(A))^2 = x^2 + y^2 - (x cos(A) + y sin(A))^2

Take the square root of both sides:

x sin(A) - u cos(A) = sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)

Subtract x sin(A) from both sides:

-u cos(A) = sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) - x sin(A) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)

Divide both sides by -cos(A):

u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)

Subtract x sin(A) from both sides:

u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or -u cos(A) = -x sin(A) - sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)

Divide both sides by -cos(A):

Answer:  u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or u = sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) + x tan(A)

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I’m pretty sure it’s the last one. :)
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