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Mathematics

1 answer:

Phoenix [80]3 years ago

7 0

It appears to be 1500m or 1.5km

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Find the angle vector of 7j +10 k,i +6j+6k,-4i+9j+6k

aleksandrvk [35]

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Right angled and isosceles

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2 years ago

Verify the identity (tan x + 1)^2 + (tan x-1)^2= 2 sec^2 x

Elina [12.6K]

$(\tan x+1)^2+(\tan x-1)^2=2\sec^2x\\\\\text{use}\ \tan x=\dfrac{\sin x}{\cos x}\\\\L_s=\left(\dfrac{\sin x}{\cos x}+\dfrac{\cos x}{\cos x}\right)^2+\left(\dfrac{\sin x}{\cos x}-\dfrac{\cos x}{\cos x}\right)^2\\\\=\left(\dfrac{\sin x+\cos x}{\cos x}\right)^2+\left(\dfrac{\sin x-\cos x}{\cos x}\right)^2\\\\=\dfrac{(\sin x+\cos x)^2}{\cos^2x}+\dfrac{(\sin x-\cos x)^2}{\cos^2x}\\\\\text{use}\ (a\pm b)^2=a^2\pm2ab+b^2$

$=\dfrac{\sin^2x+2\sin x\cos x+\cos^2}{\cos^2x}+\dfrac{\sin^2x-2\sin x\cos x+\cos^2}{\cos^2x}\\\\=\dfrac{\sin^2x+2\sin x\cos x+\cos^2+\sin^2x-2\sin x\cos x+\cos^2}{\cos^2x}\\\\=\dfrac{2\sin^2x+2\cos^2x}{\cos^2x}=\dfrac{2(\sin^2x+\cos^2x)}{\cos^2x}\\\\\text{use}\ \sin^2x+\cos^2x=1\\\\=\dfrac{2(1)}{\cos^2x}=2\cdot\dfrac{1}{\cos^2x}=2\left(\dfrac{1}{\cos x}\right)^2\\\\\text{use}\ \sec x=\dfrac{1}{\cos x}\\\\=2(\sec^2x)=2\sec^2x=R_s\\\\L_s=R_s\Rightarrow The\ identity$

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3 years ago

This statement is justified by which property of equality?

Galina-37 [17]

Answer:

symmetric property

Step-by-step explanation:

with symmetric property if x=y then both values on either side of the equal sign will be equal

4 0

2 years ago

dnw snow storm Francisco had 17 inches of snow on his lawn.the temperature then increased in the snow begin to melt at a consist

stich3 [128]

Answer:

Step-by-step explanation:

(equation: 17-2.5=2)

17-2.5=2

-2.5

17=2

17 divided by 2

8.5 is the

he would have 8.5 inches of snow on his lawn.

4 0

2 years ago