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Setler79 [48]
2 years ago
8

Solve V = 10t +7f for f​

Mathematics
2 answers:
mariarad [96]2 years ago
5 0
7f + 10t = V

7f = V - 10t

f = (V - 10t)/7
Elanso [62]2 years ago
3 0

Answer:

f = (V - 10t) / 7.

Step-by-step explanation:

V = 10t +7f

Add -10t to both sides:

V - 10t = 7f

Now divide both sides by 7:

f = (V - 10t) / 7.

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The set of all points that are equidistant from two points
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3. A bag contains 4 white, 3 blue, and 6 red marbles. A marble is drawn from the bag, replaced,
gladu [14]

Answer:

Hope this helps! If I could have brainliest I'm trying to rank up.

Step-by-step explanation:

First find the probability of each color being drawn.

We need to find the total number of marbles first.

4 + 3 + 6 = 13

Everything will be over 13.

Probability of a white marble being drawn --> 4/13

Probability of a blue marble being drawn --> 3/13

Probability of a red marble being drawn --> 6/13

Now to find the probabilities of more than one being drawn, we can multiply.

Part A:

6/13*6/13=36/169

Part B:

3/13*3/13=9/169

Part C:

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Part D:

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8 0
2 years ago
Of all the students in a class, 2/5 of them
Marrrta [24]

Answer:

it is 20%

Step-by-step explanation:

easy

3 0
2 years ago
Evaluate the difference quotient for the given function. Simplify your answer.
nasty-shy [4]

I suppose you mean

f(x) = \dfrac{x+5}{x+1}

Then

f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2

and the difference quotient is

\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with

\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}

4 0
2 years ago
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