Standard form is ax+by=c
normally a is positive and a and b are integres
y=mx+b
m=slope
b=yint
y=1/2x+3
minus 1/2 x both sides
-1/2x+y=3
times -2
x-2y=-6
4 is the least the amount of sides the polygon can have
Answer:
here's the answer I have in the photo and solution too
|2x - 5| - 2 = 3 |add 2 to both sides
|2x - 5| = 5 ⇔ 2x - 5 = 5 or 2x - 5 = -5 |add 5 to both sides
2x = 10 or 2x = 0 |divide both sides by 2
x = 5 or x = 0
I think it's C,But I'm not sure