Answer:
Halife of C-14 is=14(RAM÷2)
You get=7 but further more let's say after 3 half life as your question stated it may result to decimal something which is impossible (as nucleons never be decimal)
Hence after 3half life it will continue to be 7
Answer:
There are 2 sex chromosomes – X and Y. Females have 22 autosomes and two X chromosomes, i.e., 22 + XX, while males have 22 autosomes and an X and Y chromosome each, i.e., 22 + XY. hope it helps.
basically 22
Explanation:
Answer:
C) 30,000
Explanation:
According to the given information, the bacterial mRNA consists of about 800 nucleotides. Three consecutive nucleotides together make one genetic codon which in turn codes for one specific amino acid in the protein encoded by this mRNA.
So, an mRNA with 800 nucleotides will have total 800/3 = 266.67 or 266 genetic codes. The protein encoded by this mRNA would have a total of 266 amino acids.
Given that one amino acid imparts 110 units to the molecular weight of the protein, the protein with 266 amino acids have the molecular weight= 266 x 110 = 29260, that is about 30,000.
