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sukhopar [10]
2 years ago
10

PLZ ANSWER QUICKLY ALSO THIS QUESTION IS FOR SCIENCE

Biology
2 answers:
ZanzabumX [31]2 years ago
8 0

Answer:These variations in air pressure are due to temperature differences caused by variations in solar energy received at the surface of the earth. The sunlight absorbed by the ground depends on the latitude of the location, the slope and the underlying surface. ... The air pressure on Earth is not the same everywhere.

Explanation: i looked it up

Juli2301 [7.4K]2 years ago
4 0

Answer:

Warm air rises, creating a low pressure zone; cool air sinks, creating a high pressure zone.

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Which of the following is a food chain that can be made fro this food web
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B

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How are environmental issues and food production related?
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Answer: Food consumption and production have a considerable impact on the environment.  Food production contributes

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You are a botanist looking at the plant color in a new breed of Snapdragon. The two parent plants are Blue and Green and when yo
irakobra [83]

Answer:

Incomplete dominance is the inheritance pattern where the dominant allele did not mask the recessive allele completely and form a mix of both alleles. Here the inheritance is the incomplete inheritance. The ratio of F2 generation is 1:2:1.

Given:

R1R1 = 42

R2R2 = 39

R1R2 = 86

Total R1 alleles = 2*42+86 = 170

Total R2 alleles = 2*39+86 = 164

Total alleles = 334

Frequency of allele R1 = 170/334 = 0.51

Frequency of allele R2 = 164 / 334 = 0.49

Expected number of each phenotype:

Total population = 167

Blue = R1R1 = 0.51 * 0.51 * 167 = 43.44

Green = R2R2 = 0.49 * 0.49 * 167 = 40.10

Cyan = 2*R1*R2 = 2*0.51*0.49*167 = 83.46

Phenotype     Observed(O)    Expected (E)    O-E      (O-E)2     (O-E)2/E

Blue                 42                   43.44               -1.44       2.0736     0.0477

cyan                86                   83.46                 2.54     6.4516     0.0773

green              39                    40.1                    -1.1       1.2100      0.0302

Total              167                     167                                               0.1552

Chi-square value = 0.155

Degrees of freedom = no. of phenotypes – 1

Df = 3-1 = 2

Critical value = 5.99

Chi-square value of 0.155 is less than the critical value of 5.99. So we accept the null hypothesis.

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2 years ago
FLUS Full Time Grades 6-3
Serga [27]

Answer:

A would be the correct answer I'm sure

Explanation:

Have a nice day

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3 years ago
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