If f(x)=2x squared -x, find f (3)
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Answer:
2x^2 -x +1 = 0
Step-by-step explanation:
For roots α and β, the original equation can be factored as ...
f(x) = 2(x -α)(x -β)
If we add 1 to each of those roots, the factors become ...
g(x) = 2(x -(α+1))(x -(β+1))
This can be rearranged to be ...
g(x) = 2((x -1) -α)((x -1) -β)
That is, we can get the desired equation by replacing x with x-1, effectively shifting the function right one unit.
2(x -1)² +3(x -1) +2 = 0
2x^2 -x +1 = 0
For a cartesian equation
Given r = <span>10 tan(θ) sec(θ)
Therefore,</span>the curve is a parabola opening upward with vertex (0, 0).
Given r = <span>10 tan(θ) sec(θ)
Therefore,</span>the curve is a parabola opening upward with vertex (0, 0).