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Rashid [163]
3 years ago
7

Factor each expression. 44r+352 448-16b+112c

Mathematics
1 answer:
mars1129 [50]3 years ago
8 0
<h3>First expression:</h3>

Factor 44 out of 44r+352.

44(r+8)

<h3>Second expression:</h3>

Factor −16 out of 448−16b+112c.

−16(b−7c−28)

plz mark me as brainliest :)

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What role does Geometric formulas have in our lives??
amid [387]
Geometry helps us in deciding what materials to use, what design to make and also plays a vital role in the construction process itself. Different houses and buildings are built in different geometric shapes to give a new look as well as to provide proper ventilation inside the house.

Hope that helped :)
5 0
3 years ago
DESPERATE WILL GIVE BRAINLIST AND THANKS
Bezzdna [24]

Answer: Positive

Step-by-step explanation:

A scatter plot for speed and distance is created.

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Thus if we plot on x axis distance, we find that x increases when y increases.

So we find that there is a strong positive relationship between the two variable

D=tS

where D= distance S=speed and T=time.

Since D varies directly as speed, we have positive relationship.

Hope this helps! :)

5 0
3 years ago
A woman decides to have children until she has her first boy or until she has four children, whichever comes first. Let X = numb
rusak2 [61]

Answer:

The probability of every simple event is:

P(B)=0.5

P(GB)=0.25

P(GGB)=0.125

P(GGGB)=0.0625

P(GGGG)=0.0625

Step-by-step explanation:

For simple event B, the probability is calculate as have a boy in the first birth, so: P(B)=0.5

Then, for the event GB, the probability is calculated as the multiplication of the probability of have a girl in the first birth and have a boy in the second, so:

P(GB)=<u>      0.5        </u>* <u>         0.5       </u>=0.25

           have a girl     have a boy

At the same way for the event GGB, the probability is calculated as the multiplication of the probability of have a girl in the first and second birth and have a boy in the third, so:

P(GGB)=0.5*0.5*0.5=0.125

For the event GGGB, the probability is calculated as the multiplication of the probability of have a girl in the first, second and third birth and have a boy in the fourth, so:

P(GGGB)=0.5*0.5*0.5*0.5=0.0625

Finally, for the event GGGG, the probability is calculated as the multiplication of the probability of have a girl in the first, second, third and fourth birth, so:

P(GGGG)=0.5*0.5*0.5*0.5=0.0625

3 0
3 years ago
Evaluate the following expression for w=4. w^-3 =
slega [8]
W^-3
(4)^-3 = 1/(4)^3
1/64.

The solution is 1/64.
6 0
3 years ago
Please I really need help on this one
Dima020 [189]
Radius: 2.5 centimeters
3 0
3 years ago
Read 2 more answers
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