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Sergeeva-Olga [200]
3 years ago
11

Mark the vertex of the parabola.

Mathematics
2 answers:
kirill115 [55]3 years ago
8 0

Answer:

(2,-4)

Step-by-step explanation:

its either gonna be the highest or lowest point of the arabola, based on the graph the loswest point is (2,-4)

RSB [31]3 years ago
6 0

Answer:

(2,-4)

Step-by-step explanation:

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Tony operates a skate rental company. He charges an equipment fee of $3 plus $6 per hour. Which equation represents this linear
slava [35]

Answer: A) y = 6x +3

Step-by-step explanation:

Let x represent the number of hours. $6 per hour can now be written as 6x.

Now, we must account for the $3 flat, fee and add it to 6x, getting 6x + 3

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3 years ago
Gary is using an indirect method to prove that segment DE is not parallel to segment BC in the triangle ABC shown below:
aliya0001 [1]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Based on the situation above the inequality will he use to contradict the assumption is <span>
4:10 ≠ 6:14</span>
if DE is parallel to BC
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4: (4+5) = 6 : (6 + 8)
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3 years ago
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Whats is x − 2 /3 = 1 5 /6??
AveGali [126]
Answer: 2 1/2
explanation: 1 5/6= 11/6 ; 11/6 + 2/3= 5/2 ; 5/2= 2 1/2
6 0
3 years ago
1. A flower shop wishes to add the valuable Waimea orchid to its product list. They purchase a large shipment of bulbs from a su
AysviL [449]

Answer:

The concern of the florist that these bulbs are not Waimea orchids, but a similar appearing hybrid maybe true.

Step-by-step explanation:

A Chi-square goodness of fit test can be used to perform the hypothesis test.

The hypothesis is defined as:

<em>H</em>₀: There is no difference between the observed and expected value.

<em>Hₐ</em>: There is a difference between the observed and expected value.

The test statistic is:

\chi^{2}=\sum \frac{(O-E)^{2}}{E}

The total number of Waimea orchid bulbs is, 60.

7x + 5x + 4x + 4x = 60

20x = 60

x = 3

The expected number of Waimea orchid bulbs are:

Blue = 7 × 3 = 21

Red = 5 × 3 = 15

Violet = 4 × 3 = 12

Orange = 4 × 3 = 12

Consider the table provided.

The test statistic value is:

\chi^{2}=\sum \frac{(O-E)^{2}}{E}=14.981

The decision rule:

The null hypothesis will be rejected if \chi^{2}\geq \chi^{2}_{\alpha, (k-1)}.

Compute the critical value as follows:

\chi^{2}_{0.05, (4-1)}= \chi^{2}_{0.05, (3)}=7.815

The test statistic value is 14.981.

\chi^{2}=14.981> \chi^{2}_{\alpha, (k-1)}=7.815

The null hypothesis will be rejected at 5% level of significance.

Conclusion:

As the null hypothesis was rejected it implies that there is a significant difference between the observed and expected value.

Thus, the concern of the florist that these bulbs are not Waimea orchids, but a similar appearing hybrid maybe true.

4 0
3 years ago
The data set represents the number of rings each person in a room is wearing.
MrRa [10]
If the data set represents the number of rings each person is wearing, being: 0,2,4,0,2,3,2,8,6, the interquartile range of the data is 2. Being, 4 as the Q1, 3 as the Q2 or median, and 6 as the Q3. Where the formula of getting the interquartile range is IQR= Q1-Q2.
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4 years ago
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