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Sergio [31]
3 years ago
6

Pls work out and give detail. Use the slope formula to determine the slope of each line.

Mathematics
1 answer:
kolbaska11 [484]3 years ago
7 0

Answer:

m=0

Step-by-step explanation:

Given

See attachment

Required

Determine the slope of the line

From the attachment, we have the following points

(x_1,y_1) = (-4,1)

and

(x_2,y_2) = (3,1)

The slope m is then calculated using:

m = \frac{y_2- y_1}{x_2 - x_1}

Substitute values for the x's and y's

m = \frac{1-1}{3 - (-4)}

m = \frac{1-1}{3 +4}

m = \frac{0}{7}

m=0

<em>Hence, the slope is 0</em>

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Answer:

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\begin{pmatrix}  &Y=0&Y=1&Y=2&Y=3&Y=4\\X=0&0.3&0.05&0.025&0.025&0.1\\ X=1&0.18&0.03&0.015&0.015&0.06 \\ X=2&0.12&0.02&0.01&0.01&0.04\end{pmatrix}

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Step-by-step explanation:

We have to construct the joint probability table with the marginal probabilities of X and Y.

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We can calculate each point of the joint probability as:

P(x,y)=P_x(x)*P_y(y)

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P(X\leq 1 \& Y \leq 1)=P(0,0)+P(0,1)+P(1,0)+P(1,1)\\\\P(X\leq 1 \& Y \leq 1)=0.3+0.05+0.18+0.03=0.56

We can calculate P(X<= 1) * P(Y<=1)

P_x(X\leq 1)=P_x(0)+P_x(1)=0.5+0.3=0.8\\\\P_y(Y\leq1)=P_y(0)+P_y(1)=0.6+0.1=0.7\\\\P_x(X\leq1)*P_y(Y\leq1)=0.8*0.7=0.56

Both calculations give the same result.

c) Probability of no violations

P(X+Y=0)=P(0,0)=0.3

d) P(X + Y <= 1)

P(X+Y \leq 1)=P(0,0)+P(0,1)+P(1,0)\\\\P(X+Y \leq 1)=0.3+0.05+0.18=0.53

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