There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
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<h2><u>Problem Solving</u>:-</h2>
2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation which describes the relation.
<h2><u>Solution</u>:-</h2>
Since the distance d varies directly as the time t, then d = kt.
Using one of the pairs of values, (2, 20), from the table, substitute the values of d and t in d = kt and solve for k.




<h2><u>Answer</u>:-</h2>
- Therefore, the constant of variation is 10.
Did you ever find the answer?
Answer:
-3<x<3
Step-by-step explanation:
let y=0
0=x^2-9
0=(x+3)(x-3)
x=-3 and x=+3
X=4
Y=-0.5
Do you need an explanation?