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Anit [1.1K]
3 years ago
15

The amount that two groups of students spent on snacks in one day is shown in the dot plots below. Which statements about the me

asures of center are true? Select three choices. The mean for Group A is less than the mean for Group B. The median for Group A is less than the median for Group B. The mode for Group A is less than the mode for Group B. The median for Group A is 2. The median for Group B is 3.

Mathematics
1 answer:
RUDIKE [14]3 years ago
8 0

Answer:

  • The mean for Group A is less than the mean for Group B.
  • The median for Group A is less than the median for Group B.
  • The mode for Group A is less than the mode for Group B.

Step-by-step explanation:

First, we can find the measures of center for each group.

<u>Group A</u>

Mode: 1

Median: (1 + 2) / 2 = 3 / 2 = 1.5

Mean: (1 * 5 + 2 * 4 + 3) / 10 = (5 + 8 + 3) / 10 = 16 / 10 = 1.6

<u>Group B</u>

Mode: 3

Median: 92 + 3) / 2 = 5 / 2 = 2.5

Mean: (1 * 3 + 2 * 2 + 3 * 4 + 5) / 10 = (3 + 4 + 12 + 5) / 10 = 24 / 10 = 2.4

From here, we can see that...

  • The mean for Group A is less than the mean for Group B.
  • The median for Group A is less than the median for Group B.
  • The mode for Group A is less than the mode for Group B.

Hope this helps!

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earnstyle [38]
The sum of the interior angle of a polygon is 720°, thus the value of w will be obtain as follows:
size of each angle is
720/6=120°
thus
8w=120
solving for w we get'
(8w)/8=120/8
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Answer: w=15°


6 0
3 years ago
A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
bonufazy [111]

Answer:

A(t) = 300 -260e^(-t/50)

Step-by-step explanation:

The rate of change of A(t) is ...

A'(t) = 6 -6/300·A(t)

Rewriting, we have ...

A'(t) +(1/50)A(t) = 6

This has solution ...

A(t) = p + qe^-(t/50)

We need to find the values of p and q. Using the differential equation, we ahve ...

A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50

0 = 6 -p/50

p = 300

From the initial condition, ...

A(0) = 300 +q = 40

q = -260

So, the complete solution is ...

A(t) = 300 -260e^(-t/50)

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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.

6 0
3 years ago
Read 2 more answers
Can someone help with explanation?
ch4aika [34]

Answer:

Step-by-step explanation:

multiply 7 times 4 then you add that when you

add 4+1=5 then you multiply those two

8 0
2 years ago
At a music store, 8 CDs cost $32. How much 15 CDs cost at this store?
Goryan [66]

Answer:

$60

Step-by-step explanation:

Divide $32 by 8 (= $4), then multiply that ($4) by 15, and the answer is $60.

Hope this helps :)

3 0
3 years ago
Read 2 more answers
2^{51} mod 22 in words, two to the power of fifty-one mod twenty-two
andreyandreev [35.5K]

Since 2⁵ = 32, and

2⁵ ≡ 32 ≡ 10 (mod 22),

we have

2⁵¹ ≡ 2 • 2⁵⁰ ≡ 2 • (2⁵)¹⁰ ≡ 2 • 10¹⁰ (mod 22)

Now consider 10¹⁰ (mod 22):

10 = 2 • 5

10¹⁰ ≡ 2¹⁰ • 5¹⁰ ≡ (2⁵)² • 5¹⁰ ≡ 10² • 5¹⁰ ≡ 2² • 5¹² (mod 22)

so that

2⁵¹ ≡ 2³ • 5¹² (mod 22)

Now consider 5¹² (mod 22):

5 and 22 are coprime, and ɸ(22) = 10 (where ɸ(<em>n</em>) is the Euler totient function). By Euler's theorem,

5¹² ≡ 5² • 5¹⁰ ≡ 5² • 1 ≡ 25 ≡ 3 (mod 22)

and so

2⁵¹ ≡ 2³ • 3 ≡ 24 ≡ 2 (mod 22)

Another, more tedious method: Start with smaller powers of 2 and look for a pattern.

2 ≡ 2 (mod 22)

2² ≡ 4 (mod 22)

2³ ≡ 8 (mod 22)

2⁴ ≡ 16 (mod 22)

2⁵ ≡ 32 ≡ 10 (mod 22)

2⁶ ≡ 2 • 32 ≡ 2 • 10 ≡ 20 (mod 22)

2⁷ ≡ 2 • 20 ≡ 40 ≡ 18 (mod 22)

2⁸ ≡ 2 • 18 ≡ 36 ≡ 14 (mod 22)

2⁹ ≡ 2 • 14 ≡ 28 ≡ 6 (mod 22)

2¹⁰ ≡ 2 • 6 ≡ 12 (mod 22)

2¹¹ ≡ 2 • 12 ≡ 24 ≡ 2 (mod 22)

2¹² ≡ 2 • 2 ≡ 4 (mod 22)

and so on, with a cyclic pattern of length 10. That is, 2^{10k+1}\equiv2\pmod{22} for any integer <em>k</em> ≥ 0. So 2⁵¹ ≡ 2 (mod 22).

3 0
3 years ago
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