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castortr0y [4]
3 years ago
10

Which expression is equivalent to (a^-3 b/a^-5 b3)^-3? Assume a=0, b=0.

Mathematics
1 answer:
prohojiy [21]3 years ago
7 0
Use:\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\\\(ab)^n=a^nb^n

\left(\dfrac{a^{-3}b}{a^{-5}b^3}\right)^{-3}=\left(a^{-3-(-5)}b^{1-3}\right)^{-3}=\left(a^{-3+5}b^{-2}\right)^{-3}=\left(a^2b^{-2}\right)^{-3}\\\\=(a^2)^{-3}(b^{-2})^{-3}=a^{2(-3)}b^{-2(-3)}=a^{-6}b^6=\dfrac{b^6}{a^6}
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8b+4 - 4b + 2<br><br>I need this answer asap​
spin [16.1K]
The answer should be 2(2b+3)
6 0
3 years ago
Read 2 more answers
Kristen has 64 coins in her bank. She has $9.25 in dimes and quarters. How many dimes and quarters does she have?
Stella [2.4K]
D= # of dimes
q= # of quarters

QUANTITY EQUATION:
d + q= 64

COST EQUATION:
0.10d + 0.25q= $9.25


STEP 1:
multiply quantity equation by -0.10 to be able to eliminate the d term in step 2

(-0.10)(d + q)= (-0.10)(64)
-0.10d - 0.10q= -6.40


STEP 2:
add equation from step 1 to cost equation to eliminate the d term and solve for q

Add
0.10d + 0.25q= $9.25
-0.10d - 0.10q= -6.40

0.15q= 2.85
divide both sides by 0.15

q= 19 quarters


STEP 3:
substitute q value in step 2 into either original equation to find d value

d + q= 64

d + 19= 64
subtract 19 from both sides

d= 45 dimes


CHECK:
0.10d + 0.25q= $9.25
0.10(45) + 0.25(19)= 9.25
4.50 + 4.75= 9.25
9.25= 9.25


ANSWER: There are 45 dimes and 19 quarters.

Hope this helps! :)
7 0
3 years ago
Solve the equation given in Exercise 15 with and without using the LCD of the fractions. Are your answers the same?
Colt1911 [192]
Without LCD :
1/2(4x + 6) = 1/3(9x - 24)
2x + 3 = 3x - 8
2x - 3x = -8 - 3
-x = - 11
x = 11

with LCD :
1/2(4x + 6) = 1/3(9x - 24) ...multiply by 6
3(4x + 6) = 2(9x - 24)
12x + 18 = 18x - 48
12x - 18x = -48 - 18
-6x = - 66
x = -66/-6
x = 11

Yes, the answers are the same :)

3 0
3 years ago
Please help fast and show your work
Wittaler [7]

Step-by-step explanation:

85-83=2

2/85×100

<h3>=2.3%</h3>
3 0
3 years ago
if the diameter of the front wheels on the locomotive is 4 ft what is the diameter of the front wheels on the model. Express the
Leto [7]

Question is Incomplete, Complete question is given below.

Consider a model of a train locomotive that has a similarity transformation map of x arrow right 48x from the model to the actual locomotive when answering the question.

If the diameter of the front wheels on the locomotive is 4 feet, what is the diameter of the front wheels on the model? Express the answer in inches.

Answer:

The diameter of front wheel on the model is 1 inch.

Step-by-step explanation:

Given:

Let diameter of the front wheel on the model be 'x'.

Actual diameter of front wheel = 4 feet

Now given that ratio model to actual = \frac{x}{48x}= \frac{1}{48}

Now we can say that  ratio model to actual is equal to ratio of model diameter of front wheel to actual diameter of front wheel.

framing in equation form we get;

\frac{x}{4}=\frac{1}{48}\\\\x=\frac{4}{48} = \frac{1}{12} \ ft.

Now we know that;

\frac{1}{12}\ ft = 1 \ in.

Hence The diameter of front wheel on the model is 1 inch.

6 0
3 years ago
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