The answer should be 2(2b+3)
D= # of dimes
q= # of quarters
QUANTITY EQUATION:
d + q= 64
COST EQUATION:
0.10d + 0.25q= $9.25
STEP 1:
multiply quantity equation by -0.10 to be able to eliminate the d term in step 2
(-0.10)(d + q)= (-0.10)(64)
-0.10d - 0.10q= -6.40
STEP 2:
add equation from step 1 to cost equation to eliminate the d term and solve for q
Add
0.10d + 0.25q= $9.25
-0.10d - 0.10q= -6.40
0.15q= 2.85
divide both sides by 0.15
q= 19 quarters
STEP 3:
substitute q value in step 2 into either original equation to find d value
d + q= 64
d + 19= 64
subtract 19 from both sides
d= 45 dimes
CHECK:
0.10d + 0.25q= $9.25
0.10(45) + 0.25(19)= 9.25
4.50 + 4.75= 9.25
9.25= 9.25
ANSWER: There are 45 dimes and 19 quarters.
Hope this helps! :)
Without LCD :
1/2(4x + 6) = 1/3(9x - 24)
2x + 3 = 3x - 8
2x - 3x = -8 - 3
-x = - 11
x = 11
with LCD :
1/2(4x + 6) = 1/3(9x - 24) ...multiply by 6
3(4x + 6) = 2(9x - 24)
12x + 18 = 18x - 48
12x - 18x = -48 - 18
-6x = - 66
x = -66/-6
x = 11
Yes, the answers are the same :)
Step-by-step explanation:
85-83=2
2/85×100
<h3>=2.3%</h3>
Question is Incomplete, Complete question is given below.
Consider a model of a train locomotive that has a similarity transformation map of x arrow right 48x from the model to the actual locomotive when answering the question.
If the diameter of the front wheels on the locomotive is 4 feet, what is the diameter of the front wheels on the model? Express the answer in inches.
Answer:
The diameter of front wheel on the model is 1 inch.
Step-by-step explanation:
Given:
Let diameter of the front wheel on the model be 'x'.
Actual diameter of front wheel = 4 feet
Now given that ratio model to actual = 
Now we can say that ratio model to actual is equal to ratio of model diameter of front wheel to actual diameter of front wheel.
framing in equation form we get;

Now we know that;

Hence The diameter of front wheel on the model is 1 inch.