All categories

3 years ago

Point A(1,3) is reflected across the x-axis to create Point A’. The line y=2x-5 pass through point A’

Mathematics

1 answer:

Studentka2010 [4]3 years ago

5 0

Answer:

True

Step-by-step explanation:

Best to use a graphing calculator or graph it onto paper, after you change Point A after it reflected over the x - axis. The rule for reflection over the x-axis is (x, y) ---> (x, -y), so all you would need to do is change the positive 3 (the y value of A) into -3. So A' = (1, -3)

You might be interested in

Answers to the worksheet how did the light dress up in costume party

asambeis [7]

Neon $\left \{ {{y=2} \atop {x=2}} \right.$

4 0

3 years ago

Find the value of x, circles and angles

lorasvet [3.4K]

Answer:

x = 50

Step-by-step explanation:

When two secants intersect in the interior of a circle, the angles formed are the average of the arc an angle and its vertical intercept. In this case, our angle, 73, should be the average of x and 96. We can translate this to an equation and solve:

$\frac{x+96}{2} = 73$

x + 96 = 146

x = 50

4 0

3 years ago

Write an equation for the function graphed below. k(t)=

zloy xaker [14]

Answer:

I think that the equation would be Y= -2X^2-4X-4 .

Step-by-step explanation:

Hope it wad helpful :)

5 0

3 years ago

Namd the terms in the expression <br><br>3n + 4p + 2 <br>

Jobisdone [24]

The terms are 3n, 4p, and 2.

4 0

3 years ago

Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe

8090 [49]

Answer:

The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

Step-by-step explanation:

Let's define:

R₁ = rate of bus 1, this is the faster one.

R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

R₂ = R₁ - 14mi/h

R₁*2h + R₂*2h = 304 mi

The first step is to replace the first equation in the second one, to get:

R₁*2h + (R₁ - 14mi/h)*2h = 304 mi

And now we can solve this for R₁.

R₁*2h + R₁*2h - 14mi/h*2h = 304 mi

R₁*4h - 28mi = 304mi

R₁*4h = 304mi + 28mi = 332mi

R₁ = 332mi/4h = 83mi/h

The faster bus moves at 83mi/h

And we know that the slower one moves at 14mi/h slower than this, then:

R₂ = R₁ - 14mi/h = 83mi/h - 14mi/h = 69 mi/h

7 0

3 years ago