Question

Find point P that divides segments AB into a 2:3 ratio.

Answer 1

$\bf ~~~~~~~~~~~~\textit{internal division of a line segment} \\\\\\ A(-3,1)\qquad B(3,5)\qquad \qquad \stackrel{\textit{ratio from A to B}}{2:3} \\\\\\ \cfrac{A\underline{P}}{\underline{P} B} = \cfrac{2}{3}\implies \cfrac{A}{B} = \cfrac{2}{3}\implies 3A=2B\implies 3(-3,1)=2(3,5)\\\\ -------------------------------\\\\ P=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)$

$\bf -------------------------------\\\\ P=\left(\cfrac{(3\cdot -3)+(2\cdot 3)}{2+3}\quad ,\quad \cfrac{(3\cdot 1)+(2\cdot 5)}{2+3}\right) \\\\\\ P=\left(\cfrac{-9+6}{5}~~,~~\cfrac{3+10}{5} \right)\implies P=\left(-\frac{3}{5}~~,~~\frac{13}{5} \right)$