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creativ13 [48]
2 years ago
13

The width of a rectangle is 5x -5.5 feet and the length is 5.5x + 10 feet. Find the perimeter of the

Mathematics
2 answers:
Valentin [98]2 years ago
7 0

21x+9ft, since x has no value that I know of. Otherwise sub that number in for x and complete the equation.

Explanation: it’s a rectangle so the width and length are the same so just multiple the width and length by themselves add all like terms (x’s and numbers) you’ll get the answer.
saul85 [17]2 years ago
4 0

Answer:

130ft

Step-by-step explanation:

5x -5.5 = -27.5

5x -5.5 = 27.5 + 10 = 37.5

27.5 x 2 = 55

27.5 + 10 = 37.5 x 2 = 75

55 + 75 = 130 ft

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Answer:

(a) {(1, 2), (2,4), (3,6), (4 , 8), (1,3), (3,5), (5,7)}

Step-by-step explanation:

add them

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2 years ago
Who know how to do this ?
nadya68 [22]
It seems to me this just wants you to add the 3 equations.
2m + 2n +5p


3 0
3 years ago
Please help me I’ve been struggling
Shalnov [3]
Your answer will be 5.
Hope this helps!
3 0
3 years ago
Hiring the bus will cost $25 a day for the driver, $2 per mile traveled, and $3 for gas per mile traveled. The field trip will t
tatiyna

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4 0
2 years ago
Read 2 more answers
M1 Matrix is:
harkovskaia [24]

Answer:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

Step-by-step explanation:

Given matrix M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)

The Inverse of a 2X2 matrix

A=\left(\begin{array}{ccc}a&b\\c&d\end{array}\right)

can be found using the following:

A^{-1}=\dfrac{1}{ad-bc} \left(\begin{array}{ccc}d&-b\\-c&a\end{array}\right)

Therefore:

M^{-1}=\dfrac{1}{(5*-5)-(3*-8)} \left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=-1\left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)

Next, we find the product M^{-1}M

M^{-1}M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\\=\left(\begin{array}{ccc}-5*-5+3*-8&-5*3+3*5\\-8*-5+5*-8&-8*3+5*5\end{array}\right)\\=\left(\begin{array}{ccc}1&0\\0&1\end{array}\right)

Therefore:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

NOTE: The multiplication of a matrix and its inverse always gives the identity matrix as seen above,

7 0
3 years ago
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