3x+3=3y ⇒ 3y-3x=3 ⇒3(y-x)=3 ⇒ y-x=1
2x-6y=2 ⇒ 2(x-3y)=2 ⇒ x-3y=1
We must to collect two equations.
x's is lost;
y-3y=2
-2y=2
y=-1 ; x-3.(-1)=1 ⇒ x=-2
Answer is (-2,-1)
Duruvdidhu you can get my stuff for you today if not I’ll just ask my buddy to come get it
Solution (1) using angles of sectors:
Area of A = pi r^2 x 90/360 = 4.9
Area of B = pi r^2 x 270/360 = 14.2
Check: Area of A/B = 4.9/14.72 = 1/3 (as given)
Solution (2) using given info:
Area of B + Area of A = area of circle
Area of B + 1/3 Area of B = 3.14 * (2.5)^2 = 19.625
4/3 Area of B = 19.625
Area of B = 3/4 * 19.625
Area of B = 14.72
Area of A = 1/3 * 14.72 = 4.9
There is more solutions to this problem , like polar coordinate integration , and so on. for more just request.
The correct answer to your question is C.
