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tigry1 [53]
3 years ago
7

Evaluate the geometric series. Help me!!

Mathematics
1 answer:
aleksklad [387]3 years ago
3 0

Answer:

255

Step-by-step explanation:

The n th term of a geometric series is

a_{n} = a(r)^{n-1}

where a is the first term and r the common ratio

1(2)^{n-1} ← is the n th term

with a = 1 and r = 2

The sum to n terms of a geometric series is

S_{n} = \frac{a(r^n-1)}{r-1}, thus

S_{8} = \frac{1(2^8-1)}{2-1}

    = 2^{8} - 1 = 256 - 1 = 255

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Answer:

53

Step-by-step explanation:

i had to use this old method (pic related).

8 0
3 years ago
A Triangle has an angle that measures 137.3 degrees. The other two angles are in a ratio of 3:4. What are the measures of those
Andreyy89
So we start off by subtracting 137.3 from 180 getting 42.5. If you add the ratios up (3+4) you get 7 and 7 should equal 42.5. thus,

42.5/7= 85/14

(85/14)*3=18.2 or (255/14 to be exact)
(85/14)*4= 24.29 or (170/7 to be exact)
8 0
3 years ago
Solve the equation 6x + 12 = 4x - 18
kenny6666 [7]

Answer:

X = -15

Step-by-step explanation:

6X +12 = 4X -18

Subtract 4X from both sides

2X +12 = -18

Subtract 12 from both sides

2X = -30

Divide both sides by 2

X = -15

So basically just have the unknown on one side and normal numbers on the other. Make sure you do the same thing on both sides.

Mark me as brainliest if this helps!

4 0
3 years ago
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Im not sure how to find the missing angle
LuckyWell [14K]

Answer:

Step-by-step explanation:

the question is asking for the length of the side labeled x

use Pythagoras'  theorem to find that side

where c = x   because c represents the hypotenuse in the theorem and x is on the hypotenuse in this problem

c = \sqrt{a^{2} + b^{2} }

sooo  plug in a = 14 and b = 10

c = \sqrt{14^{2} + 10^{2} }

c = \sqrt{196+100}

c = \sqrt{296}

c= 17.20465.....  ( that's the approx. length of side x in the problem )

since this is a right triangle we could use trigonometry to find the two angles use SOH CAH TOA  to remember how those functions fit on the triangle.

Sin(Ф)=Opp/Hyp  Cos(Ф)=Adj/Hyp  Tan(Ф)=Opp/Adj

since we know the Hyp (hypotenuse) and the side adjacent will be the side with the 10 soooo...

Cos(Ф)=10/17.20465

Ф = arcCos(10/17.20465)

Ф = 54.4623°  is the angle on the side with 10

the side with 14 then has an angle of 35.5376°

:)

5 0
3 years ago
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