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3 years ago

Two points are plotted in the coordinate plane at (-3,7) and (-3,-9). What is the distance between them

Mathematics

1 answer:

Alchen [17]3 years ago

5 0

Answer:

Step-by-step explanation:

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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

guajiro [1.7K]

Answer:

5 - x

Step-by-step explanation:

Given:

$f(x)=25-x^2$

$g(x)=x+5$

$\begin{aligned}\left(\dfrac{f}{g}\right)(x) & = \dfrac{f(x)}{g(x)}\\\\ & = \dfrac{25-x^2}{x+5}\\\\& = \dfrac{(5-x)(5+x)}{(x+5)}\\\\& = \dfrac{(5-x)(x+5)}{(x+5)}\\\\& = 5-x\end{aligned}$

8 0

2 years ago

Read 2 more answers

Please help!!!!!!!!!!!!!!

tiny-mole [99]

Answer:

53.1 degrees

Step-by-step explanation:

use sohcahtoa

sin(x) = 12/15

sin(x) = 0.8

sin-1(0.8) = 53.1301

5 0

3 years ago

Use linear approximation to approximate √25.3 as follows.

Sophie [7]

The idea is to use the tangent line to $f(x)=\sqrt x$ at $x=25$ in order to approximate $f(25.3)=\sqrt{25.3}$ .

We have

$f(x)=\sqrt x\implies f(25)=\sqrt{25}=5$

$f'(x)=\dfrac1{2\sqrt x}\implies f'(25)=\dfrac1{10}$

so the linear approximation to $f(x)$ is

$L(x)=f(5)+f'(5)(x-5)=5+\dfrac{x-5}{10}=\dfrac x{10}+\dfrac92$

Hence $m=\frac1{10}$ and $b=\frac92$ .

Then

$f(25.3)\approx L(25.3)=\dfrac{25.3}{10}+\dfrac92=\boxed{7.03}$

4 0

3 years ago

Determine if its possible to form a triangle using the set of segments with the given measurement. explain please! 12 m, 5 m, 18

IRINA_888 [86]

Adding together the shorter two sides results in 17 m. If these two sides were laid end to end, the sum of their sides (17 m) would be less than the length of the third side. Thus, NO triangle could be constructed with this set of line segments.

6 0

3 years ago

Simplify the expression 30x^6/3x^-2

Ne4ueva [31]

Answer:

$30x^{4}$

Step-by-step explanation:

6 0

2 years ago