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sukhopar [10]
3 years ago
5

Which of the following is the correct midpoint formula

Mathematics
1 answer:
GarryVolchara [31]3 years ago
6 0

Step-by-step explanation:

Hey there!

The midpoint formula is;

midpoint(x,y) = ( \frac{x1 + x2}{2}, \frac{y1 + y2}{2}  )

Where, (x1), (y1), (x2) and (y2) are the given coordinates.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Answer: No.

Step-by-step explanation:

I guess that here we have the statement:

If the sum of two numbers is odd----> can their quotient be an odd number?

first, for n an integer number, we have that:

an odd number can be written as 2n + 1

an even number can be written as 2n.

The sum of two numbers is only odd if one of them is odd and the other even.

Then we have a number that is 2n and other that is 2k + 1, for n and k integer numbers.

Now, let's see if the quotient can also be an odd number.

One way to think this is:

There is an odd number such that when we multiply it by another odd number, the result is an even number?

no, and i can prove it as:

let 2k + 1 be an odd number, and 2j + 1 other.

the product is:

(2k + 1)*(2j + 1) = 2*(2*k*j + k + j) + 1

and as k and j are integers, also does 2*k*j + k + j, so:

2*(2*k*j + k + j) + 1 is an odd number.

This says that the product of two odd numbers is always odd, then we never can have that the quotient between an even number and an odd number is odd.

4 0
3 years ago
Round 12.034 to the nearest tenth
vovangra [49]
The answer is 12.  Thanks (;
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(2x^9y^n) (4x²y^10)-8x^11 y^20                        i say the answer 1 or 10

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4 0
2 years ago
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valkas [14]
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4 years ago
Tom's stockbroker offers an investment that is compounded continuously at an annual interest rate of 3.7%. If Tom wants a return
Anettt [7]

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It'll take 38.3 years to obtain the desired return of $25,000.

Step-by-step explanation:

In order to solve a continuosly coumponded interest question we need to apply the correct formula that is given bellow:

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Where M is the final value, C is the initial value, r is the interest rate and t is the time at which the money was applied. Since he wants an return of $25,000 his final value must be the sum of the initial value with the desired return. So we have:

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e^(0.037*t) = 33000/8000

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ln[e^(0.037*t)] = ln(4.125)

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t = 38.3 years

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