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BlackZzzverrR [31]

3 years ago

5

4. If 7a = 14, then 12a -

2 answers:

givi [52]3 years ago

8 0

Answer:

24

Step-by-step explanation:

the value of a is 2, therefore 7x2=14 and 12x2=24

Alisiya [41]3 years ago

4 0

Answer: a=2

Step-by-step explanation: Well when we look at 7a = 14 how did we get to 14? Well, 7 times 2 equals 14 correct? so, we know that the variable a must equal 2. We then need some answer for 12a = __. We will need to use what we learned from the first problem which was that a equaled 2. Therefore 12a = 24.

Hope this is what you were looking for! :)

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Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5

hjlf

The rule of geometric sequence is ⇒⇒⇒ a * r^(n-1)
Where a is the first term and r is the common ratio
for the given sequence √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5

5 0

2 years ago

Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi

miss Akunina [59]

Answer:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

Step-by-step explanation:

1st boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a$

Equation:

$y=ax^2 -2ax+c$

The y-coordinate of the vertex:

$y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1$

Solve:

$c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}$

Parabola equation:

$y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}$

2nd boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0$

Equation:

$y=ax^2+c$

The y-coordinate of the vertex:

$y_v=a\cdot 0^2+c\Rightarrow c=-7$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-7\\ \\64a-7=1$

Solve:

$a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7$

Parabola equation:

$y=\dfrac{1}{8}x^2 -7$

System of two equations:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

7 0

3 years ago

Read 2 more answers

You deposit $800 in an account that earns simple interest at an annual rate of 5%.

S_A_V [24]

Step-by-step explanation:

$800 × 5% = $40

for 1 year, I earn $40

100 ÷ 40 = 2 remainder 2

Therefore I would have to leave the money in for at least 3 years to earn $100

7 0

3 years ago

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What is the constant difference for a hyperbola with foci (-3.5, 0) and (3.5, 0) and a point on the hyperbola (3. 5, 24)?

OLga [1]

I do not understand the question

8 0

2 years ago

Please can someone help me im going to failed if i don't get help

kupik [55]

Answer:

good

Step-by-step explanation:

5 0

1 year ago