2(x+4) - (y•8) when x=1/8 and y=3/16 A 11/4 B 65/2 C 21/4 D 27/5

Please help me... :(

mr_godi [17]

Answer:

6

Step-by-step explanation:

Think of it as a ratio. The recipe calls for 2:3. If Jason used 4, then you need to match the other side.

4/2=2

So you need to multiply 3 by 2 to find the match.

3x2=6

The ratio is 4:6, so Jason uses 6 teaspoons of baking powder.

-hope it helps

4 0

3 years ago

A manufacturer has been selling 1400 television sets a week at $450 each. A market survey indicates that for each $21 rebate off

GuDViN [60]

Correct question is;

A manufacturer has been selling 1400 television sets a week at $450 each. A market survey indicates that for each $21 rebate offered to a buyer, the number of sets sold will increase by 210 per week

A) Find the demand function (price p as a function of units sold x).

p(x)=______

(B) How large a rebate should the company offer the buyer in order to maximize its revenue?

$=_____

Answer:

A) p(x) = (-1/10)x + 590

B) Rebate = $170

Step-by-step explanation:

A) We are told that p(x) is the demand function and x is the number of TV sets sold per week.

Now, since for each $21 rebate offered, the number of sets sold increases by 210 per week, it means that the slope here of this demand function is; m = -21/210 = -1/10

Now, he has been selling 1400 TV sets a week at $450 each. This means; p(1400) = $450

Thus, the demand function will be;

p(x) - 450 = (-1/10)(x - 1400)

Expanding the RHS;

p(x) - 450 = (-1/10)x + 140

Add 450 to both sides to get;

p(x) = (-1/10)x + 140 + 450

p(x) = (-1/10)x + 590

B) Formula for revenue is;

R = price × quantity sold

Our demand function is p = (-1/10)x + 590

Making x the subject, we have;

x = 5900 - 10p

x is quantity sold.

Thus,

R = p(5900 - 10p)

R = 5900p - 10p²

Maximum price will occur at dR/dP = 0

Thus;

dR/dP = 5900 - 20p

At dR/dP = 0,we have;

20p = 5900

p = 5900/20

p = $280

Thus, rebate = 450 - 280 = $170

6 0

3 years ago

Determine whether the points (–3,–2) and (3,2) are in the solution set of the system of inequalities below. y ≤ ½x + 2 y < –2

lana [24]

Given:

The system of inequalities:

$y\leq \dfrac{1}{2}x+2$

$y$

To find:

Whether the points (–3,–2) and (3,2) are in the solution set of the given system of inequalities.

Solution:

A point is in the solution set of the given system of inequalities if it satisfies both inequalities.

Check for the point (-3,-2).

$-2\leq \dfrac{1}{2}(-3)+2$

$-2\leq -1.5+2$

$-2\leq 0.5$

This statement is true.

$-2$

This statement is also true.

Since the point (-3,-2) satisfies both inequalities, therefore (-3,-2) is in the solution set of the given system of inequalities.

Now, check for the point (3,2).

$2$

This statement is false because $2>-9$ .

Since the point (3,2) does not satisfy the second inequality, therefore (3,2) is not in the solution set of the given system of inequalities.

7 0

3 years ago

K is no greater than 9? Write>,<.

alekssr [168]

Greater than symbol is ">"
But since he mentioned "NO greater than" then it's the opposite of greater than, which means "K" is less than "9"

K<9

4 0

3 years ago

a sum of RS 500 is in the form of denominators of RS5 & RS 10..if the total no. of notes is 90 ,find the no. of notes of eac

Katarina [22]

Let rs.5 denominations be x , then rs 10 denominations will be 90-x

then total amount 5x + 10(90-x) which is rs.500

5x + 10(90-x) = 500

900 - 5x = 500
400 = 5x
therefore x = 80
therefore no. of rs.5 is 80
no. of rs.10 is 90-x = 90-80 = 10

8 0

4 years ago