Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
<u>a) Determine the value for the first order size generated based on 0.41</u>
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
<u>b) Value of the last order generated based on random number (0.6)</u>
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
<u>c) Average order size </u>
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
Answer:
x = 41/3
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
7(1x - 3) = 4(x + 5)
<u>Step 2: Solve for </u><em><u>x</u></em>
- Simplify: 7(x - 3) = 4(x + 5)
- Distribute: 7x - 21 = 4x + 20
- Subtract 4x on both sides: 3x - 21 = 20
- Add 21 on both sides: 3x = 41
- Divide 3 on both sides: x = 41/3
<u>Step 3: Check</u>
<em>Plug in x to verify it's a solution.</em>
- Substitute: 7(1(41/3) - 3) = 4(41/3 + 5)
- Multiply: 7(41/3 - 3) = 4(41/3 + 5)
- Subtract/Add: 7(32/3) = 4(56/3)
- Multiply: 224/3 = 224/3
Here, we see that 224/3 is indeed equivalent to 224/3. ∴ x = 41/3 is a solution to the equation.
And we have our final answer!
A is the correct answer.......
Here is the work shown:
x^2-x-20
A is the correct answer because when using the distributive property it is the only example that results in x^2-x-20.
(x+4)(x-5)
x*x=x^2, x*-5=-5x, 4*x=4x, 4*-5=-20. Now combine all alike terms for your final answer. x^2-x-20..
please vote my answer brainliest. thanks!
355,000 would be the right answer. the 6 behind the 4 is the factor true. like if it was a 4 it would be 354,000
