Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Answer:
15x - 4y =-50 -----(i)
3x - 2y=-16 --------(ii)
Using Substitution
From (i)
15x=4y-50
x=4y-50/15
Substitute x=4y-50/[15] into eqn (ii)
3x - 2y= -16
3[4y-50]/15 - 2y =-16
Multiply through by 15 to clear the fraction
3(4y - 50) - 30y=-240
12y - 150 -30y=-240
12y-30y=-240+150
-18y = -90
y=90/18
y=5.
Substitute into any eqn of choice to get x
3x - 2y=-16
3x - 2(5)=-16
3x - 10=-16
3x=-16+10
3x=-6
x=-6/3
x=-2.
x= -2
y=5
The fractions which cannbe formed are: 2/3, 3/2, 2/5, 5/2, 3/5 and 5/3.
Now, we find the products with the third number:
2/3*5= 10/3 = 3.33 > 2
3/2*5 = 15 >2= 7.5 > 2
2/5*3= 6/5 (rejected)
5/2*3 = 15/2 > 2
3/5*2= 6/5 (rejected)
5/3*2 = 15/2 = 7.5> 2
Answer:
Step-by-step explanation:
Answer:
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Step-by-step explanation: