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Mekhanik [1.2K]

2 years ago

8

You draw two cards from a standard deck of 52 cards. What is the probability of drawing a club and then a diamond consecutively

from the deck without replacement?

2 answers:

maxonik [38]2 years ago

8 0

Answer:

C.13/204

Step-by-step explanation:

Multiply the two probabilities to find the compound probability.

P(club and diamond) = 13/52 × 13/51 = 13/204

BabaBlast [244]2 years ago

7 0

Answer:

C

Step-by-step explanation:

Multiply the two probabilities to find the compound probability.

P(club and diamond) =

13

52

×

13

51

=

13

204

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four families go to the cinema. the reid family take 2 adults and 2 children for £18 ; the mghee family take 1 senior, 2 adults

RoseWind [281]

Answer:

$\pounds 26.50$

Step-by-step explanation:

Let

x = cost for one adult

y = cost for one child

z = cost for one senior.

<u>The Reid family:</u>

take 2 adults and 2 children and paid $2x+2y$ that is $\pounds 18$ , so

$2x+2y=18$

<u>The Mghee family:</u>

take 1 senior, 2 adults and 1 child and paid $x+2x+y$ that is $\pounds 18.50$ , so

$x+2x+y=18.50$

<u>The Griffiths family:</u>

take 1 senior and 3 adults and paid $z+3x$ that is $\pounds 19.50$ , so

$z+3x=19.50$

You get the system of three equations:

$\left\{\begin{array}{l}2x+2y=18\\ \\z+2x+y=18.50\\ \\z+3x=19.50\end{array}\right.$

From the first equation:

$2y=18-2x\\ \\y=9-x$

From the third equation:

$z=19.50-3x$

Substitute them into the second equation:

$19.50-3x+2x+9-x=18.50\\ \\-3x+2x-x=18.50-19.50-9\\ \\-2x=-10\\ \\2x=10\\ \\x=5$

Then

$y=9-5=4\\ \\z=19.50-3\cdot 5=19.50-15=4.50$

Hence,

the cost for one adult is $\pounds 5$

the cost for one child is $\pounds 4$

the cost for one senior is $\pounds 4.50$

<u>The Linton family</u> takes 1 senior, 2 adults and 3 children and paid

$\pounds 4.50+2\cdot \pounds 5+3\cdot \pounds 4=\pounds 26.50$

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Step-by-step explanation:

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