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Nimfa-mama [501]
2 years ago
13

The area is 2 times the radius times the circumference. True or False?

Mathematics
2 answers:
choli [55]2 years ago
7 0
I think it’s true have a good day
ZanzabumX [31]2 years ago
4 0

Answer:

I believe its true

Step-by-step explanation:

You have to find circumference of a circle. Pi comes here because of its ratio. 2 and r comes because it equals the diameter. So pi times 2 times r is basically circumference over diameter times diameter which gives circumference.

Hope this helps

All the love, Ya boi Fraser :)

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\frac{2*2*7}{1}\ or\ 28
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How to find matrics M
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\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -4M=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\qquad(*) \\\\M=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]\to4M=\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]

(*)\qquad\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\\\\left[\begin{array}{ccc}9-4a&7-4b\\-4-4c&2-4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\.\qquad\qquad\qquad\qquad\ \ \ \Downarrow\\(_{11})\qquad9-4a=-3\ \ \ |-9\\-4a=-12\ \ \ \ |:(-4)\\a=3\\\\(_{12})\qquad7-4b=3\ \ \ \ |-7\\-4b=-4\ \ \ \ |:(-4)\\b=1

(_{21})\qquad-4-4c=4\ \ \ \ |+4\\-4c=8\ \ \ \ |:(-4)\\c=-2\\\\(_{22})\qquad2-4d=-18\ \ \ \ |-2\\-4d=-20\ \ \ \ \ |:(-4)\\d=5\\\\Answer:\ A.\ M=\left[\begin{array}{ccc}3&1\\-2&5\end{array}\right]

3 0
3 years ago
12(3+m) <br> A.36m<br> B.36+m<br> C.36+12m<br> D.3m+12m<br> PLEASSSSEEE HELP ASAP 15
kherson [118]

Answer:

C. 36+12m

Step-by-step explanation:

When you distribute a number outside the parenthesis, you multiply it to all numbers nor letters in the parenthesis. Hopes this helps

8 0
3 years ago
Can anyone help me please?
miss Akunina [59]

Answer:

  5. -18x^3y^4 +54x^2y^4

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Step-by-step explanation:

Use the distributive property. The factor outside parentheses multiplies each term inside parentheses.

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<h3>5.</h3>

  (9xy)(-2x^2y^3+6xy)=(9xy)(-2x^2y^3)+(9xy)(6xy^3)\\\\=\boxed{-18x^3y^4+54x^2y^4}

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<h3>6.</h3>

  (3x-5)(2x-10)=3x(2x-10)-5(2x-10)\\\\=6x^2-30x-10x+50=\boxed{6x^2-40x+50}

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2 years ago
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