Answer:
- m = 4/3; b = -4
- m = 3; b = -6
Step-by-step explanation:
In each case, <em>solve for y</em>. You do this by getting the y-term by itself, then dividing by the coefficient of y.
<h3>1.</h3>
-3y = -4x +12 . . . . . subtract 4x
y = 4/3x -4 . . . . . . . divide by -3
The slope is 4/3; the y-intercept is -4.
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<h3>2.</h3>
y = 3x -6 . . . . . . divide by 2
The slope is 3; the y-intercept is -6.
_____
<em>Additional comment</em>
Whatever you do to one side of the equation, you must also do to the other side. When we say "subtract 4x", that means 4x is subtracted from both sides of the equation. The reason for doing that in the first equation is to eliminate the 4x term from the left side.
(Sometimes, you may see operations described as "move ...". There is no property of equality called "move." There are <em>addition</em>, <em>subtraction</em>, <em>multiplication</em>, <em>division</em>, and <em>substitution</em> properties of equality. Any equation solving process will make use of one or more of these.)
Answer:
50, 60, 50, and 60
Step-by-step explanation:
xy = 3000
2x + 2y = 220
Rewrite the second equation
y = -x + 110
Substitute this into the first equation.
x(-x + 110) = 3000
-x^2 + 110x - 3000
Divide by -1
x^2 - 110x + 3000
(x - 60) (x - 50)
x = 60, 50
When x = 60, y = 50 and vice versa, so the sides are 50, 60, 50, and 60.
For the first image, the median range would be 88. In order to find the median, you'll place all your numbers in numerical order (smallest to largest). If there are an odd amount of numbers, find the one directly in the middle. If there is an even amount, you'll take the two most central ones and find the mean, that will tell you the median. Therefore, B (88) would be the answer to your first one.
The second one would be C (20.4). It's asking for the mean. In order to find the mean of a set of numbers, you'll simply add up all of the numbers and divide by how many numbers are in your number set. That gives you the mean.
Your answer will be 2+\sqrt{3} will be your answer
We need the statements in order to answer
